Do you still need the answer, because im working on the same question..
The answer is C. $48 for 6 days is 48(6), then subtract the amount of money Rufus will spend, which is 5(32.5), so it's 48(6)-5(32.5)
The probability any one system works is 0.99
So the probability of any one system failing is 1-0.99 = 0.01, so basically a 1% chance of failure for any one system
Multiply out the value 0.01 with itself four times
0.01*0.01*0.01*0.01 = 0.000 000 01
I'm using spaces to make the number more readable
So the probability of all four systems failing is 0.00000001
Subtract this value from 1 to get
1 - 0.00000001 = 0.99999999
The answer is 0.99999999 which is what we'd expect. The probability of at least one of the systems working is very very close to 1 (aka 100%)
0.035x+0.045x=427.50
0.08x=427.50
x=427.50/0.08
x=5343.75
x+x+1500=5343.75
2x=5343.75-1500
2x=3843.75
x=1921.88 first
1921.88+1500=3421.88 second
I believe it would be 0 fr
