Ok so assume that if you have
xy=0 then x and y=0
-1/4(x^2-4x+3)>0
multiply both sides by -4 to clear fraction (-4/-4=1)
flip sign
x^2-4x+3<0
factor
(x-3)(x-1)<0
we know that (+) times (-)=(-) and
(-) times (-)=(+) so we don't want them to be both negative, we want different sign
we cannnot have 3 since it would be (0)(2)<0 which is false
we cannot have 1 either since (-2)(0)<0 is also false
lets see if the solution is in betwen 3 and 1 or outside of 3 and 1
ltry 2
2^3-4(2)+3<0
8-8+3<0
3<0
false
therefor it is outside ie
x>3 and x<1
Answer:
A hash mark.
Step-by-step explanation:
The marks or intervals on a ruler are called hash marks. That particular hash mark measures 0 millimeters. Hash marks are used for telling the measurement of an object.
Answer:
4 i think im not sure
Step-by-step explanation:
Subtract yy from both sides of the equation.
4x=8−y4x=8-y
y=kx+2y=kx+2
Divide each term by 44 and simplify.
Tap for more steps...
x=2−y4x=2-y4
y=kx+2
Answer:
-25
Step-by-step explanation:
Evaluate -x - 6 x + 10 where x = 5:
-x - 6 x + 10 = -5 - 6×5 + 10
-6×5 = -30:
-5 + -30 + 10
-5 - 30 + 10 = 10 - (5 + 30):
10 - (5 + 30)
5 + 30 = 35:
10 - 35
10 - 35 = -(35 - 10):
-(35 - 10)
| 3 | 5
- | 1 | 0
| 2 | 5:
Answer: -25
