Mrs. Kelso and Mr. Bonham gave each their student a small bag of colored tiles. The student each counted the number of purple ti
les they received . The box plots display the data for both classes.
1 answer:
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Answer: The answer is 381.85 feet.
Step-by-step explanation: Given that a window is 20 feet above the ground. From there, the angle of elevation to the top of a building across the street is 78°, and the angle of depression to the base of the same building is 15°. We are to calculate the height of the building across the street.
This situation is framed very nicely in the attached figure, where
BG = 20 feet, ∠AWB = 78°, ∠WAB = WBG = 15° and AH = height of the bulding across the street = ?
From the right-angled triangle WGB, we have
and from the right-angled triangle WAB, we have'
Therefore, AH = AB + BH = h + GB = 361.85+20 = 381.85 feet.
Thus, the height of the building across the street is 381.85 feet.
The value of x so that lines s and t are parallel is 12
<h3 /><h3>How to find angles involving parallel lines?</h3>The angle are alternate exterior angles.
Therefore, alternate exterior angle theorem states that when two parallel lines are intersected by a transversal, then the exterior angles formed on either side of the transversal are equal.
Hence,
7x - 20 = 4x + 16
7x - 4x= 16 + 20
3x = 36
x = 36 / 3
x = 12
Therefore, the value of x is 12.
learn more on parallel lines here: brainly.com/question/4427808
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