Answer:
I guess it is the Answer C
Answer:
True, see proof below.
Step-by-step explanation:
Remember two theorems about continuity:
- If f is differentiable at the point p, then f is continuous at p. This also applies to intervals instead of points.
- (Bolzano) If f is continuous in an interval [a,b] and there exists x,y∈[a,b] such that f(x)<0<f(y), then there exists some c∈[a,b] such that f(c)=0.
If f is differentiable in [0,4], then f is continuous in [0,4] (by 1). Now, f(0)=-1<0 and f(4)=3>0. Thus, we have the inequality f(0)<0<f(4). By Bolzano's theorem, there exists some c∈[0,4] such that f(c)=0.
Answer:
C.?
Step-by-step explanation:
wheres the pic??
You can use elimination to solve systems of equations with 3 equations. I know how to solve systems of equatons with 3 equations, but I use a different process, I don't know how to use the elimination method.
Answer:
y-intercept : -7
x-intercept : 7/5
Step-by-step explanation:
<em>FOR</em><em> </em><em>Y</em><em> </em><em>intercept</em><em> </em><em>put</em><em> </em><em>x</em><em> </em><em>=</em><em>0</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>equation</em>
<em>FOR</em><em> </em><em>x</em><em> </em><em>intercept</em><em> </em><em>put</em><em> </em><em>y</em><em>=</em><em>0</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>equa</em><em>tion</em><em>!</em>
<em> </em><em>✌️</em><em>;</em><em>)</em>
