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dolphi86 [110]
3 years ago
6

Y=5

Mathematics
1 answer:
Ymorist [56]3 years ago
5 0
15. = slope would be 7 and y-int would be -4
16. = slope would be -2/5 and y-int would be 0
17. = doesn’t have a y variable

slope intercept form is y=mx+b with the m being the slope and the b being the y-int. in some cases where the equation is not in this form you have to change it so it is in that form by using opposite operations
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What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that t
Inga [223]

Answer:

f(2n)-f(n)=log2

b.lg(lg2+lgn)-lglgn

c. f(2n)/f(n)=2

d.2nlg2+nlgn

e.f(2n)/(n)=4

f.f(2n)/f(n)=8

g. f(2n)/f(n)=2

Step-by-step explanation:

What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that the number of milliseconds the algorithm uses to solve the problem with input size n is each of these function? [Express your answer in the simplest form pos- sible, either as a ratio or a difference. Your answer may be a function of n or a constant.]

from a

f(n)=logn

f(2n)=lg(2n)

f(2n)-f(n)=log2n-logn

lo(2*n)=lg2+lgn-lgn

f(2n)-f(n)=lg2+lgn-lgn

f(2n)-f(n)=log2

2.f(n)=lglgn

F(2n)=lglg2n

f(2n)-f(n)=lglg2n-lglgn

lg2n=lg2+lgn

lg(lg2+lgn)-lglgn

3.f(n)=100n

f(2n)=100(2n)

f(2n)/f(n)=200n/100n

f(2n)/f(n)=2

the time will double

4.f(n)=nlgn

f(2n)=2nlg2n

f(2n)-f(n)=2nlg2n-nlgn

f(2n)-f(n)=2n(lg2+lgn)-nlgn

2nLg2+2nlgn-nlgn

2nlg2+nlgn

5.we shall look for the ratio

f(n)=n^2

f(2n)=2n^2

f(2n)/(n)=2n^2/n^2

f(2n)/(n)=4n^2/n^2

f(2n)/(n)=4

the time will be times 4 the initial tiote tat ratio are used because it will be easier to calculate and compare

6.n^3

f(n)=n^3

f(2n)=(2n)^3

f(2n)/f(n)=(2n)^3/n^3

f(2n)/f(n)=8

the ratio will be times 8 the initial

7.2n

f(n)=2n

f(2n)=2(2n)

f(2n)/f(n)=2(2n)/2n

f(2n)/f(n)=2

5 0
2 years ago
a container of candy is shaped like a cylinder and has a volume of 125.6 cubic centimeters. If the heights of the container is 1
Elenna [48]

The radius of the container is 2 centimeter

<h3><u>Solution:</u></h3>

Given that a container of candy is shaped like a cylinder

Given that volume = 125.6 cubic centimeters

Height of conatiner = 10 centimeter

To find: radius of the container

We can use volume of cylinder formula and obatin the radius value

<em><u>The volume of cylinder is given as:</u></em>

\text {volume of cylinder }=\pi r^{2} h

Where "r" is the radius of cylinder

"h" is the height of cylinder and \pi is constant has value 3.14

Substituting the values in formula, we get

\begin{array}{l}{125.6=3.14 \times r^{2} \times 10} \\\\ {r^{2}=\frac{125.6}{31.4}} \\\\ {r^{2}=4}\end{array}

Taking square root on both sides,

r = \sqrt{4}\\\\r = 2

Thus the radius of the container is 2 centimeter

4 0
3 years ago
A. NOT CONGRUENT<br><br> b. AAS<br><br> c. SSS<br><br> d. ASA<br><br> e. SAS
alexdok [17]

Answer:

......................

5 0
3 years ago
I can’t figure out how to solve this for a. I’ve tried multiple ways but still have not come up with an answer.
abruzzese [7]

Answer:

a = 33

Step-by-step explanation:

IN a parallelogram consecutive angles are supplementary, thus

5a - 52 + 5a - 98 = 180, that is

10a - 150 = 180 ( add 150 to both sides )

10a = 330 ( divide both sides by 10 )

a = 33

8 0
3 years ago
Read 2 more answers
All four of the box plots lie on the same scale and contain the same number of data points. Identify the box plot that best repr
zvonat [6]

Answer:

It's the boxplot with these (**) Not symetric and the middle of the box isnt

alined, hope this helps

5 0
3 years ago
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