Answer:
A piecewise function.
Step-by-step explanation:
The problem you showed is a <em>piecewise function.</em>
In this problem, you have to plug in 3 for the value x.
However, if you take a look at the conditions that value x has, it never says that x can equal 3. <em>Thus, this function cannot be true.</em>
<em>Way to check this input is undefined: </em>
Plug in 3 for the variable x. On the first function, your output will be 4. On the second function, your output will be 8.
According to the definition of a function, a function can have many inputs but only one output. In this case, this function has one input, that is 3, but produces two outputs.
There are two ways to do this.
The first way is to algebraically find (f+g)(x) first and plug in x = 5 later. Doing that method leads us to
(f+g)(x) = f(x) + g(x)
(f+g)(x) = 6x+3 + x-4
(f+g)(x) = 7x-1
(f+g)(5) = 7(5)-1
(f+g)(5) = 34
OR
you can compute f(5) and g(5) first, then add up those sub-results to get
f(x) = 6x+3
f(5) = 6(5)+3
f(5) = 33
g(x) = x-4
g(5) = 5-4
g(5) = 1
Adding up these results gives: (f+g)(5) = f(5) + g(5) = 33+1 = 34
Either way, the final answer is 34
Answer:
50
Step-by-step explanation:
Answer:
22x + 16
Step-by-step explanation:
No, your answer is not correct. you added l +b but you were supposed to add
L+B+L+B
Answer: -13.3
Step-by-step explanation:
