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m_a_m_a [10]
3 years ago
14

U6 D2 Identify the Dependent Quantity

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
5 0

Answer:

B: How many boxes of candles Frank will buy.

Step-by-step explanation:

It would be b, since the amount of boxes Frank buys is affected by how old his grandmother is. This makes it the dependent quantity.

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For an integer x,x squared minus x will always produce an even value
yuradex [85]

Answer:

Step-by-step explanation:

Not exactly sure what your question is - I am assuming that it is something like:

Show/prove that for any integer x, x^2 - x is even.

Suppose that x is an even integer.  The product of an even integer and any other integer is always even (x = 2n, so x * y = 2 n * y which is even.  Therefore x^2 is even.  An even minus an even is even.  (The definition of an even number is that it is divisible by 2 or has a factor of 2.  So the difference of even numbers could be written as 2*( the difference of the two numbers divided by 2); therefore the difference is even)

Suppose that x is an odd integer.  The product of 2 odd numbers is odd - each odd number can be written as the sum of an even number and 1; multiplying the even parts with each other and 1 will produce even; multiplying the 1's will produce 1, so the product can be written as the sum of an even number and 1 - which is an odd number.  The difference between two odd numbers is even - the difference between the even parts is even (argument above), the difference between 1 and 1 is zero, so the result of the difference is even.

x^2 is therefore even if x is even and odd if x is odd; The difference x^2 - x is even by the arguments above.

5 0
3 years ago
Jocelyn invested $390 in account paying an interest rate of 2.7% compounded daily. Assuming no deposits or withdrawals are made,
Bond [772]

Answer:

Someone ples answer this

Step-by-step explanation:

It’s so hard

8 0
3 years ago
Alicia can row 6 miles downstream in the same time it takes her to row 4 miles upstream.She rows downstream miles/hour faster th
disa [49]

Answer:

Option D. 9 mi/hr downstream, 6 mi/hr upstream

Step-by-step explanation:

<u><em>The complete question is</em></u>

Alicia can row 6 miles downstream in the same time it takes her to row 4 miles upstream. She rows downstream 3 miles/hour faster than she rows upstream. Find Alicia’s rowing rate each way

Define the variables

Let

x -----> Alicia's rowing rate downstream in miles per hour

y ----> Alicia's rowing rate upstream in miles per hour

we know that

The rate is equal to the distance divided by the time

so

The time is equal to the distance divided by the rate

we have

\frac{6}{x}=\frac{4}{y}

4x=6y

x=1.5y -----> equation A

x=y+3 ----> equation B

equate equation A and equation B

1.5y=y+3

1.5y-y=3

0.5y=3

y=6

<em>Find the value of x</em>

x=1.5(6)=9

therefore

Alicia's rowing rate downstream is 9 mi/h

Alicia's rowing rate upstream is 6 mi/h

6 0
4 years ago
18 pizzas were orderd for a holiday party at reedy creek elementary there were cheese and pepperoni pizzas of 1/3 of the pizza w
viktelen [127]

Answer:

12

Step-by-step explanation:

We know that 1/3 of a pizza is cheese meaning that 6 pizzas are made of cheese and there are only two leaving the rest pepperoni and 12 are left if we subtract the cheese pizzas minus the 18 pizzas we have 12 which are pepperoni.

8 0
3 years ago
A force of 3 pounds is required to hold a spring stretched 0.6 feet beyond its natural length. how much work (in foot-pounds) is
ioda

The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound

<h3>Data obtained from the question</h3>

From the question given above, the following data were obtained:

  • Force (F) = 3 pounds
  • Extension (e) = 0.6 feet
  • Work done (Wd) =?

<h3>How to determine the spring constant</h3>
  • Force (F) = 3 pounds
  • Extension (e) = 0.6 feet
  • Spring constant (K) =?

F = Ke

Divide both sides by e

K = F/ e

K = 3 / 0.6

K = 5 pound/foot

Thus, the spring constant of the spring is 5 pound/foot

<h3>How to determine the work done</h3>
  • Spring constant (K) = 5 pound/foot
  • Extention (e) = 0.7 feet
  • Work done (Wd) =?

Wd = ½Ke²

Wd = ½ × 5 × 0.7²

Wd = 2.5 × 0.49

Wd = 1.23 foot-pound

Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound

Learn more about spring constant:

brainly.com/question/9199238

#SPJ1

5 0
2 years ago
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