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3 years ago

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The motor of a four wheeler traveling along a muddy trail generates an average power of 7.05 104 W when moving at a constant spe

ed of 15 m/s. When pulling a log along the trail at the same speed, the engine must generate an average power of 8.15 104 W. What is the tension in the tow rope pulling the log?

1 answer:

Gennadij [26K]3 years ago

7 0

Answer:

$F=733.33 N$

Explanation:

Power is the work to make a motion in a determine time also the al the work is the force make in a distance so:

$P=\frac{W}{t}$

$W=F*d$

Replacing

$P=F*\frac{d}{t}$

Knowing that the velocity is:

$v=\frac{d}{t}$

So:

$P=F*v$

Solve to F to determinate the tension that in this case is the force in the rope

$F=\frac{P}{v}$

The power is the total power so:

$P=8.15x10^4W-7.05x10^4W=11x10^3W$

$F=\frac{3kW}{15\frac{m}{s}}=733.33 N$

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Answer:

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The wavelength of a frequency of 1070 khz is 280.3 m.

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The wavelength of a frequency of 835.6 Mhz is 0.35m.

Explanation:

The wavelength can be determined by the following equation:

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Where c is the speed of light, $\lambda$ is the wavelength and $\nu$ is the frequency.

Notice that since it is electromagnetic radiation, equation 1 can be used. Remember that light propagates in the form of an electromagnetic wave.

<em>a). 100.2 MHz (typical frequency for FM radio broadcasting)</em>

Then, $\lambda$ can be isolated from equation 1:

$\lambda = \frac{c}{\nu}$ (2)

since the value of c is $3x10^{8}m/s$ . It is necessary to express the frequency in units of hertz.

$\nu = 100.2 MHz . \frac{1x10^{6}Hz}{1MHz}$ ⇒ $100200000Hz$

But $1Hz = s^{-1}$

$\nu = 100200000s^{-1}$

Finally, equation 2 can be used:

$\lambda = \frac{3x10^{8}m/s}{100200000s^{-1}}$

$\lambda = 2.99 m$

Hence, the wavelength of a frequency of 100.2 Mhz is 2.99m.

<em>b. 1070 kHz (typical frequency for AM radio broadcasting) (assume four significant figures)</em>

<em> </em>

$\nu = 1070kHz . \frac{1000Hz}{1kHz}$ ⇒ $1070000Hz$

But $1Hz = s^{-1}$

$\nu = 1070000s^{-1}$

Finally, equation 2 can be used:

$\lambda = \frac{3x10^{8}m/s}{1070000s^{-1}}$

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Hence, the wavelength of a frequency of 1070 khz is 280.3 m.

<em>c. 835.6 MHz (common frequency used for cell phone communication) </em>

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But $1Hz = s^{-1}$

$\nu = 835600000s^{-1}$

Finally, equation 2 can be used:

$\lambda = \frac{3x10^{8}m/s}{835600000s^{-1}}$

$\lambda = 0.35 m$

Hence, the wavelength of a frequency of 835.6 Mhz is 0.35m.

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