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2 years ago

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The motor of a four wheeler traveling along a muddy trail generates an average power of 7.05 104 W when moving at a constant spe

ed of 15 m/s. When pulling a log along the trail at the same speed, the engine must generate an average power of 8.15 104 W. What is the tension in the tow rope pulling the log?

1 answer:

Gennadij [26K]2 years ago

7 0

Answer:

$F=733.33 N$

Explanation:

Power is the work to make a motion in a determine time also the al the work is the force make in a distance so:

$P=\frac{W}{t}$

$W=F*d$

Replacing

$P=F*\frac{d}{t}$

Knowing that the velocity is:

$v=\frac{d}{t}$

So:

$P=F*v$

Solve to F to determinate the tension that in this case is the force in the rope

$F=\frac{P}{v}$

The power is the total power so:

$P=8.15x10^4W-7.05x10^4W=11x10^3W$

$F=\frac{3kW}{15\frac{m}{s}}=733.33 N$

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A ____ is the time required for one half of the nuclei in a radio- ____ isotope to decay.

sukhopar [10]

Answer:

A half-life is the time required for one half of the nuclei in a radio- active isotope to decay.

Explanation:

A radio-active isotope is an isotope which undergoes radioactive decay.

Radioactive decay is a spontaneous process in which the nucleus of an atom changes its state (turning into a different nucleus, or de-exciting), emitting radiation, which can be of three different types: alpha, beta or gamma.

The half-life of a radio-active isotope is the time required for half of the nuclei of the initial sample to decay.

The law of radio-active decay can be expressed as follows:

$N(t) = N_0 (\frac{1}{2})^{t/t_{1/2}}$

where

N(t) is the number of undecayed nuclei left at time t

N0 is the initial number of nuclei

t is the time

$t_{1/2}$ is the half-life

We see that when $t=t_{1/2}$ (that means, when 1 half-life has passed), the number of undecayed nuclei left is

$N(t) = N_0 (\frac{1}{2})^{t_{1/2}/t_{1/2}}=N_0 (\frac{1}{2})^1=\frac{N_0}{2}$

So, half of the initial nuclei.

5 0

2 years ago

A garden hose with a diameter of 0.64 in has water flowing in it with a speed of 0.46 m/s and a pressure of 1.9 atmospheres. At

STALIN [3.7K]

Answer:

(a).The speed of the water in the nozzle is 3.014 m/s.

(b). The pressure in the nozzle is 1.86 atm.

Explanation:

Given that,

Nozzle diameter = 0.25 in = 0.00635 m

Hose pipe diameter = 0.64 in = 0.016256 m

Pressure = 1.9 atm =192518 Pa

(a). We need to calculate the speed of the water in the nozzle

Flow Speed at the inlet pipe will be given by using Continuity Equation

$Q_{1}=Q_{2}$

$v_{1}A_{1}=v_{2}A_{2}$

$v_{1}=v_{2}\times(\dfrac{A_{2}}{A_{1}})$

Where, A = area of pipe

$A=\pi\times \dfrac{d^2}{4}$

$v_{1}=v_{2}\times(\dfrac{d_{2}^2}{d_{1}^2})$

Put the value into the formula

$v_{1}=0.46\times\dfrac{(0.016256)^2}{(0.00635)^2}$

$v_{1}=3.014\ m/s$

The speed of the water in the nozzle is 3.014 m/s.

(b). We need to calculate the pressure in the nozzle

Using Bernoulli's Theorem,

$P_{1}+\dfrac{1}{2}\rho\times v_{1}^2+\rho gh_{1}=P_{2}+\dfrac{1}{2}\rho\times v_{2}^2+\rho gh_{2}$

Where, $h_{1}=h_{2}$

$P_{1}+\dfrac{1}{2}\rho\times v_{1}^2=P_{2}+\dfrac{1}{2}\rho\times v_{2}^2$

$P_{1}=P_{2}+\dfrac{1}{2}\rho(v_{2}^2-v_{1}^2)$

Put the value into the formula

$P_{1}=192518 +\dfrac{1}{2}\times1000\times((0.46)^2-(3.014)^2)$

$P_{1}=188081.702\ Pa$

$P=1.86\ atm$

Hence, (a).The speed of the water in the nozzle is 3.014 m/s.

(b). The pressure in the nozzle is 1.86 atm.

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2 years ago

The frequency of violet light is 7.5x10 to the 14th power hertz. What is the wavelength?

Verizon [17]

Wavelength times frequency = speed of light
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Wavelength in meters = 300,000 divided by 7.5E14

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Mamont248 [21]

That's wave 'diffraction'.

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3 years ago

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kifflom [539]

Answer:

It gives our light which we need for probably everything.

Explanation:

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3 years ago

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