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ch4aika [34]
2 years ago
14

The motor of a four wheeler traveling along a muddy trail generates an average power of 7.05 104 W when moving at a constant spe

ed of 15 m/s. When pulling a log along the trail at the same speed, the engine must generate an average power of 8.15 104 W. What is the tension in the tow rope pulling the log?
Physics
1 answer:
Gennadij [26K]2 years ago
7 0

Answer:

F=733.33 N

Explanation:

Power is the work to make a motion in a determine time also the al the work is the force make in a distance so:

P=\frac{W}{t}

W=F*d

Replacing

P=F*\frac{d}{t}

Knowing that the velocity is:

v=\frac{d}{t}

So:

P=F*v

Solve to F to determinate the tension that in this case is the force in the rope

F=\frac{P}{v}

The power is the total power so:

P=8.15x10^4W-7.05x10^4W=11x10^3W

F=\frac{3kW}{15\frac{m}{s}}=733.33 N

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Un autocar que circula a 81 km/h frena uniformemente con una aceleración de -4,5 m/s2.
horsena [70]

Answer:

a) \Delta x=56.25 m

b) imagen adjunta

Explanation:

a) Primero debemos hacer la conversión de 81 km/h a m/s, esto es 22.5 m/s.

Ahora, usando la ecuacion cinemática, en un movimiento acelerado tenemos:

v_{f}^{2}=v_{0}^{2}+2a \Delta x

Queremos encontrar la posición hasta detenerse, osea vf = 0.

\Delta x=\frac{-v_{0}^{2}}{2a}

\Delta x=\frac{-22.5^{2}}{-2*4.5}

\Delta x=56.25 m

b) Para este caso el gráfico se encuentra adjunto.                                      

Espero que te sirva de ayuda!                                                                                                                                                                          

Download pdf
8 0
3 years ago
The earth and the moon exert forces on each other which forces is greater? explain
Helen [10]

Thank you for your question, what you say is true, the gravitational force exerted by the Earth on the Moon has to be equal to the centripetal force.

An interesting application of this principle is that it allows you to determine a relation between the period of an orbit and its size. Let us assume for simplicity the Moon's orbit as circular (it is not, but this is a good approximation for our purposes).

The gravitational acceleration that the Moon experience due to the gravitational attraction from the Earth is given by:

ag=G(MEarth+MMoon)/r2

Where G is the gravitational constant, M stands for mass, and r is the radius of the orbit. The centripetal acceleration is given by:

acentr=(4 pi2 r)/T2

Where T is the period. Since the two accelerations have to be equal, we obtain:

(4 pi2 r) /T2=G(MEarth+MMoon)/r2

Which implies:

r3/T2=G(MEarth+MMoon)/4 pi2=const.

This is the so-called third Kepler law, that states that the cube of the radius of the orbit is proportional to the square of the period.

This has interesting applications. In the Solar System, for example, if you know the period and the radius of one planet orbit, by knowing another planet's period you can determine its orbit radius. I hope that this answers your question.


8 0
3 years ago
A force of 250 N is applied to a 1 kg softball when struck with a bat. what is the acceleration
My name is Ann [436]
A=f/m
a=250N/1kg
a=250m/s^2
8 0
3 years ago
Phase change requires...
amm1812
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3 0
3 years ago
A firefighter of mass 81 kg slides down a vertical pole with an acceleration of 3 m/s 2 . The acceleration of gravity is 10 m/s
natima [27]

Answer:

The force of friction that acts on him is

F_k=567N

Explanation:

The firefighter with an acceleration of 3m/s^2 take the gravity acceleration as 10m/s^2 isn't necessary to know the coefficient of friction just to know the force of friction:

F=m*a

F=F_w-F_k

m*a=F_w-F_k

F_w=81kg*10m/s^2=810N

Sole to Fk

81kg*3m/s^2=810N-F_k

F_k=810N-243N

F_k=567N

4 0
2 years ago
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