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alexgriva [62]
2 years ago
15

Which of the following is an example if harmonic motion?

Physics
1 answer:
german2 years ago
3 0

Answer:

"A pendulum swinging back and forth" is an example of harmonic motion

X = Xo cos ω t

Explains the back and forth motion of the pendulum

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What causes scoliosis
klemol [59]

Answer:

<em>Scoliosis is a sideways curvature of the spine. Scoliosis is a sideways curvature of the spine that occurs most often during the growth spurt just before puberty. While scoliosis can be caused by conditions such as cerebral palsy and muscular dystrophy, the cause of most scoliosis is unknown.</em>

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3 years ago
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Write any two different between work and power?​
attashe74 [19]

Answer:

1. Work Is a type of Physical Activity  

2. Power is Basically Having control of Society

Explanation:

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3 years ago
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The position of a particle moving along the x axis depends on the time according to the equation x = ct² - bt³, where x is in me
Kamila [148]

Answer:

(a) \frac{m}{s^2}

(b) \frac{m}{s^3}

(c) 1 s

(d) 20 m

(e) 1 m

(f) 0\frac{m}{s}

(g) -12\frac{m}{s}

(h) -36\frac{m}{s}

(i) -72\frac{m}{s}

(j) -6\frac{m}{s^2}

(k) -18\frac{m}{s^2}

(l) -30\frac{m}{s^2}

(m) -42\frac{m}{s^2}

Explanation:

Since <em>x</em> is measured in meters and <em>t</em> in seconds, constants <em>a </em>and <em>b</em> must have units that gives meters when multiplied by square and cubic seconds respectivly, so that would mean \frac{m}{s^2} for <em>a </em>and \frac{m}{s^3} for <em>b</em>.

We can get the velocity <em>v </em>equation by deriving the position with respect to <em>t</em>, which gives:

v=6*t-6*t^2

And the acceleration <em>a</em> equation by deriving again:

a=6-12*t

Now for getting the maximun position between 0 and 4, we must find to points where the positions first derivate is equal to cero and evaluate those points. That is <em>v=0</em>, which gives

6*t-6*t^2=0\\6t*(1-t)=0\\t=0 or t=1

For <em>t = 0</em>,<em> x = 0</em> so the maximun position is archieved at 1 second, which gives <em>x = 1 meter</em>.

For obtaining it's displacement <em>r</em>, we can integrate the velocity from 0 seconds to 4 seconds, which gives the mean value of the position in that interval:

r=\frac{1}{4}*(2*4^3-3*4^2)m\\r= 20m

For the remaining questions, we just replace the values of <em>t</em> on the respective equations.

8 0
4 years ago
Describe the term of inertia with the respect of motion
Genrish500 [490]

Answer:

Inertia can be defined as the tendency of an object or a body to continue in its state of motion or remain at rest unless acted upon by an external force.

Explanation:

Motion can be defined as a change in the location (position) of a physical object or body with respect to a reference point.

This ultimately implies that, motion would occur as a result of a change in location (position) of an object with respect to a reference point or frame of reference i.e where it was standing before the effect of an external force.

Inertia can be defined as the tendency of an object or a body to continue in its state of motion or remain at rest unless acted upon by an external force.

Newton's First Law of Motion is also known as Law of Inertia and it states that, an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.

The inertia of an object such as a truck is greatly dependent or influenced by its mass; the higher quantity of matter in a trailer, the greater will be its tendency to continuously remain at rest.

In conclusion, inertia is applicable to all physical objects.

3 0
3 years ago
I need help in my physics class and show me how it’s done
Korolek [52]

If we have the angle and magnitude of a vector A we can find its Cartesian components using the following formula

A_x = |A|cos(\alpha)\\\\A_y = |A|sin(\alpha)

Where | A | is the magnitude of the vector and \alpha is the angle that it forms with the x axis in the opposite direction to the hands of the clock.

In this problem we know the value of Ax and Ay and we need the angle \alpha.

Vector A is in the 4th quadrant

So:

A_x = 6\\\\A_y = -6.5

So:

|A| = \sqrt{6^2 + (-6.5)^2}\\\\|A| = 8.846

So:

Ay = -6.5 = 8.846cos(\alpha)\\\\sin(\alpha) = \frac{-6.5}{8.846}\\\\sin(\alpha) = -0.7348\\\\\alpha = sin^{- 1}(- 0.7348)

\alpha = -47.28 ° +360° = 313 °

\alpha = 313 °

Option 4.

4 0
3 years ago
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