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Naya [18.7K]
3 years ago
11

10090 7 Each railroad car in a train set is 6 inches in length. The railroad track is 5 feet long. How many railroad cars can it

on the track ?​
Mathematics
2 answers:
Orlov [11]3 years ago
8 0

Step-by-step explanation:
Given,
Length of railroad car = 6 inches
The length of railroad track = 5 feet
We will convert this length into inches.
1 feet = 12 inches
5 feet = 12*5 = 60 inches
Let,
x be the number of cars.
Number of cars * Length of each car = Length of track

Dividing both sides by 6

10 cars can fit on railroad track.
denpristay [2]3 years ago
4 0

Answer: 10 railroad cars

Step-by-step explanation:

1 feet = 12 inches

Each railroad car is 6 inches in length which is half of 1 feet. If we add another railroad car, then both of them altogether will be 1 feet long.

So, if 1 feet = 2 railroad cars

then, 5 feet = 2 x 5

                    = 10 railroad cars

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2x+4y=6<br> 3x=12-6y<br> Solve by elimination
faltersainse [42]

Answer:

no solution

Step-by-step explanation:

2x + 4y = 6......reduces to x + 2y = 3

3x = 12 - 6y....reduces to x = 4 - 2y...rearranged is x + 2y = 4

so now we have :

x + 2y = 3

x + 2y = 4

ok....I dont have to go any farther to know that this has no solution because ur equations have the same slope and different y int, this means ur lines are parallel and have no solution because they never cross each others path.

5 0
3 years ago
Read 2 more answers
DEF has vertices P(-3,8) Q(-6, -4) R (1,1). if you reflect pqr across the x axis what will be the coordinates of the vertices
Rama09 [41]

P'(-3,-8) Q'(-6,4) R'(1,-1)

This should be correct! Hope I helped!

4 0
3 years ago
(−5k<br> ​3<br> ​​ −6k+1)+(−6k<br> ​2<br> ​​ +5k)
Fittoniya [83]

Remove unnecessary parenthesis.

-5k 3 - 6k +1 - 6k 2 + 5k (simplify each term) -15k - 6k + 1 - 12k +5k = -28k +1

Answer: 28k + 1

7 0
4 years ago
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An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed
masya89 [10]

Answer:

P(X\leq 1) = 0.331

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

P(X = x) = \frac{y^xe^{-y}}{x!}

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

P(X\leq 1) = P(X=0) + P(X =1)

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}

P(X = 0) = \frac{1 * e^{-2.3}}{1}

P(X = 0) = e^{-2.3}

P(X = 0) = 0.10025884372

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}

P(X = 1) = \frac{2.3 * e^{-2.3}}{1}

P(X = 1) =2.3 * e^{-2.3}

P(X = 1) = 2.3 * 0.10025884372

P(X = 1) = 0.23059534055

P(X\leq 1) = P(X=0) + P(X =1)

P(X\leq 1) = 0.10025884372 + 0.23059534055

P(X\leq 1) = 0.33085418427

P(X\leq 1) = 0.331

Hence, the required probability is 0.331

6 0
3 years ago
What is the volume of this cube?
Klio2033 [76]

Answer:

it's 6 cubic feet look you must count all the sides together also I took the test this cube has 6 sides so your answer will be 6 cubic feet ;)

Step-by-step explanation:

6 0
4 years ago
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