<h3>Step by step explanation:</h3><h3>23:67</h3><h3> 23÷67--Convert the ratio into a fraction using a÷b=a/b</h3><h3>23/67--Calculate the approximate value</h3><h3>0.343284--Round the number to the nearest ten thousand</h3><h3>0.3443--Write a decimal fraction</h3><h3>34.33/100--by definition p/100=p%</h3><h3>Answer:</h3><h2>1.34.33%</h2>
<h3>67:89</h3><h3> 67÷89--Convert the ratio into a fraction using a÷b=a/b</h3><h3>67/89--Calculate the approximate value</h3><h3>0.752809--Round the number to the nearest ten thousand </h3><h3>0.7528--Write as decimal fraction</h3><h3>75.28/100--by definition p/100=p%</h3><h3>Answer:</h3><h2>2.75.28%</h2>
<h2>That's the correct answer</h2><h2>Liked my answer </h2><h2>Brainliest</h2>
The metallurgist would need 46.875 lb of an alloy containing 30 % copper and 3.125 lb of an alloy containing 62 % copper to produce 50 lb of a third alloy.
<h3>How to estimate proportions of ingredients for an alloy by weighted averages</h3>
In this question we must prepare a <em>third</em> alloy by using correct quantity of two alloys with different <em>copper</em> concentrations. <em>Required</em> weights can be determined by applying concept of <em>weighted</em> average:
(32/100) · (50 lb) = (30/100) · x + (62/100) · (50 - x)
32 · 50 = 30 · x + 62 · (50 - x)
32 · 50 = 30 · x + 62 · 50 - 62 · x
32 · x = 30 · 50
x = 46.875
The metallurgist would need 46.875 lb of an alloy containing 30 % copper and 3.125 lb of an alloy containing 62 % copper to produce 50 lb of a third alloy.
To learn more on weighted averages: brainly.com/question/18554478
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Answer:
There are 132 red marbles and 12 black marbles
Work:
I made a ratio of 11:1 and multiplied both sides by 12 which gave me 132:12
132+12=144
Answer:
We can write this inequality in Interval Notation.
So, an inequality from -5 to -1 inclusive would just be.
[-5, -1].
The "[]" brackets mean "inclusive".
Let me know if this helps!
Answer:
1). 0.2 hours
2). 5 centimters per hour
Step-by-step explanation:
Equation which represents the depth 'd' of snow accumulated in Harper's yard during 'h' hours will be,
d = 5h
If depth of snow accumulated = 1 cm
From the given equation,
1 = 5h
h = = 0.2 hours
If duration of the snowfall = 1 hour
d = 5×1 = 5 centimeter
Therefore, snow accumulated per hour = 5 centimeters.