I think bills were 60 words because charlie was 210 so bill was 50 fewer so he is 60 and George will be twice as bills s his will be 80 words
Answer:
(d-5)
Step-by-step explanation:
we know that
The phrase"five fewer than d days" is equal to subtract 5 from the number d
so
d minus 5-----> (d-5)
Answer:
80%
Step-by-step explanation:
regular price was given as $295.
The sale of the camera was $236.
Needed Percentage of the regular price =( 236/295)
= 0.8
=(0.8 × 100%)
= 80%
Answer:
The probability that the cost is kept within budget or the campaign will increase sales is 0.88
Step-by-step explanation:
The probability that the cost is kept within budget (event A) <u>or</u> the campaign will increase sales (event B) is the <u>union</u> of the probability of those two events. By basic properties of probability, this is:
P(A ∪ B) = P(A) + P (B) - P(A ∩ B)
and for independent events:
P(A ∩ B) = P(A) * P(B)
So:
P(A ∪ B) = 0.80 + 0.40 - (0.80*0.40) = 1.20 - 0.32 = 0.88
Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
