Question

The volume of the tank is 1890 L, and the density of seawater is 1.03 g/cm3. What would be the mass of the water in the fish tank?

Answer 1

Answer:

The mass of the water in the fish tank is $1.94\times 10^6\ g$.

Explanation:

Given that,

Volume of the tank, $V=1890\ L=1.89\times 10^6\ cm^3$

The density of seawater, $d=1.03\ g/cm^3$

The density of any material is given by its mass per unit volume. Its relation is given by :

$d=\dfrac{m}{V}$

m is the mass of the water in the fish tank

$m=d\times V\\\\m=1.89\times 10^6\times 1.03\\\\m=1.94\times 10^6\ g$

So, the mass of the water in the fish tank is $1.94\times 10^6\ g$. Hence, this is the required solution.

Answer 2

Volume in cm³:

1890 * 1000 => 1890000 L

density = 1.03 g/cm³

Therefore:

mass = density * volume

mass = 1.03 * 1890000

mass = 1946700 g