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4 years ago

Currents at the surface of the ocean are

Chemistry

1 answer:

lakkis [162]4 years ago

5 0

Answer:

D. The mixing of warm and cold water

Explanation:

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(03.01 LC<br> Which of the following is not present in an atom? (1 point)

yulyashka [42]

Answer:

Protons, Neutrons, and Electrons are all in atoms so the one not present would be the Element since Elements are made of atoms.

Explanation:

4 0

3 years ago

Given the equilibrium constants for the following two reactions in aqueous solution at 25 ∘C HNO2(aq)H2SO3(aq)⇌⇌H+(aq) + NO2−(aq

krok68 [10]

Answer : The value of $K_c$ for the final reaction is, 184.09

Explanation :

The equilibrium reactions in aqueous solution are :

(1) $HNO_2(aq)\rightleftharpoons H^+(aq)+NO_2^-(aq)$ $K_{c_1}=4.5\times 10^{-4}$

(2) $H_2SO_3(aq)\rightleftharpoons 2H^+(aq)+SO_3^{2-}(aq)$ $K_{c_2}=1.1\times 10^{-9}$

The final equilibrium reaction is :

$2HNO_2(aq)+SO_3^{2-}(aq)\rightleftharpoons H_2SO_3(aq)+2NO_2^-(aq)$ $K_{c}=?$

Now we have to calculate the value of $K_c$ for the final reaction.

Now equation 1 is multiply by 2 and reverse the equation 2, we get the value of final equilibrium reaction and the expression of final equilibrium constant is:

$K_c=\frac{(K_{c_1})^2}{K_{c_2}}$

Now put all the given values in this expression, we get :

$K_c=\frac{(4.5\times 10^{-4})^2}{1.1\times 10^{-9}}=184.09$

Therefore, the value of $K_c$ for the final reaction is, 184.09

4 0

3 years ago

Calculate the following quantity: volume of 1.403 M copper(II) nitrate that must be diluted with water to prepare 575.2 mL of a

Juliette [100K]

Answer:

328 ml

Explanation:

We have given final volume =575.2 ml=0.575 L

Final concentration = 0.8012 M

We know that moles of copper(II) nitrate = final volume ×final concentration =0.8012×.0575=0.4606 moles

We have to find initial volume

So initial volume $=\frac{moles\ of \ copper(II)\ nitrate}{initial\ concentration}=\frac{0.4606}{1.403}=0.328L=328ml$

6 0

4 years ago

The equation below shows lithium reacting with nitrogen to produce lithium nitride. 6Li + N2 mc007-1.jpg 2Li3N If 12 mol of lith

andrew11 [14]

Answer is: 4.0 mol of lithium nitride would be produced.

Balanced chemical reaction: 6Li + N₂ → 2Li₃N.

n(Li) = 12 mol; amount of substance.

From chemical reaction: n(Li) : n(Li₃N) = 6 : 2 (3 : 1).

n(Li₃N) = n(Li) ÷ 3.

n(Li₃N) = 12 mol ÷ 3.

n(Li₃N) = 4 mol; amount of lithium nitride.

4 0

3 years ago

Read 2 more answers

In the

Kipish [7]

Answer: An acid-base reaction is the transfer of a proton from a proton donor ... The reaction between a Brønsted-Lowry acid and water is called acid ionization.

Explanation:

5 0

2 years ago

Read 2 more answers