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dsp73
3 years ago
8

which compound is soluble in excess ammonia solution. A. Copper (II) sulphate B. iron (II) chloride. C.Magnesium chloride. D. Ma

gnesium Chloride​
Chemistry
1 answer:
balu736 [363]3 years ago
8 0
A. Copper


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ohaa [14]
B c and d are not pure substances.
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3 years ago
How many grams (mass) are in 1.7 moles of Nickel II oxide NiO?
WARRIOR [948]

Answer:

126.99g

Explanation:

NiO has a molar mass of 74.7 g/mol. This means that one mole of nickel (II) oxide has a mass of 74.7 grams. We can use stoichiometry/dimensional analysis to figure out how many grams are in 1.7 moles.

1.7mol NiO (\frac{74.7grams}{1 mole} ) = 126.99g

3 0
3 years ago
Read 2 more answers
Can any person help me for this problem? Anyone's welcome
noname [10]

Answer:

The anode made of the impure copper

The cathode made of pure copper

The electrolyte of copper (II) sulfate CuSO₄ solution

The silver impurities at the anode due to their high tendency of accepting electrons and being a stronger reducing agent than either copper or zinc will remain relatively in place and relatively stable and will not actively take part in the oxidation reaction taking place at the anode

The zinc impurities will be the first element of the three metals to give up electrons and go into the solution as zinc ions due to their high tendency to loan out two electrons and become oxidized into Zn²⁺ ions

The drawing of the electrolytic cell created with Microsoft Visio is attached

Explanation:

5 0
3 years ago
12.0 of .500 M NaOH neutralized 6.0 ml of HCl solution. What was the molarity of the HCl
frozen [14]

The molarity of the HCl is 1 M when 12.0 of .500 M NaOH neutralized 6.0 ml of HCl solution.

Explanation:

Data given:

molarity of the base NaOH, Mbase =0. 5 M

volume of the base NaOH, Vbase = 12 ml

volume of the acid, Vacid = 6 ml

molarity of the acid, Macid = ?

The titration formula for acid and base is given as:

Mbase Vbase = Macid Vacid

Macid =\frac{0. 5 X 12}{6}

Macid = 1 M

we can see that 1 M solution of HCl was used to neutralize the basic solution of NaOH. The volume of NaOH is 12 ml and volume of HCl used is 6ml.

8 0
3 years ago
Consider the following reaction: SO2Cl2(g)⇌SO2(g)+Cl2(g) A reaction mixture is made containing an initial [SO2Cl2] of 2.2×10−2M
Andrej [43]
The value of equilibrium constant is equal to the quotient of the products raised to its stoichiometric coefficient over the reaction's reactants raised to its respective stoichiometric coeff. The equation is Kc=[SO2][Cl2]/[SO2Cl2]= [1.3*10^-2][1.3*10^-2]/[2.2*10^-2-<span>1.3*10^-2]=0.0188. The final answer is Kc=0.0188.</span>
6 0
3 years ago
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