Answer:
Area of model pond = 45.6 inch² (Approx.)
Step-by-step explanation:
Given:
Circumference of circular pond = 24 inches
Find:
Area of model pond
Computation:
Circumference of circle = 2πr
Circumference of circular pond = 2πr
24 = 2[22/7][r]
Radius r = [24 x 7] / [2 x 22]
Radius r = 3.81 inch (Approx.)
Area of circle = πr²
Area of model pond = πr²
Area of model pond = (22/7)(3.81)²
Area of model pond = [3.1428][14.5161]
Area of model pond = 45.6 inch² (Approx.)
Answer:
-81
Step-by-step explanation:
replace the numbers you were given in a or b.
so
6(-12) -1(-1 – 2 – 6(2)) + 4(-1)(2(2) -1) -12
Volume of sphere: V(s) = 4/3*pi*R^3 = (4/3)*pi*(D/2)^3 = (1/6) * pi * D^3
Volume of cube: V(c) = s^3
Volume of them is the same, I'm assuming you actually want to know the length of the cubic vertice
So s^3 = (1/6)*pi*D^3 -> s = (1/6 * pi)^1/3 * 6 = (36pi)^1/3
