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Reika [66]
3 years ago
7

The radius of a circle is 7.31. How should the circle area be reported?

Chemistry
1 answer:
Alona [7]3 years ago
7 0

I'm not sure but it should be 7.31 times 2 times 3.14 or pi

7.31 x 2 x 3.14 = 45.9068

If you need to round to the nearest tenth it will be 45.9

If you need to round to the nearest hundredth it will be 45.91

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Which is stronger - the attractive forces between water molecules and chromium and chloride ions, or the combined ionic bond str
Tju [1.3M]

Answer is: the combined ionic bond strength of CrCl₂ and intermolecular forces between water molecules.

When chromium chloride (CrCl₂) is dissolved in water, the temperature of the water increases, heat of the solution is endothermic.

Dissociation of chromium chloride in water: CrCl₂(aq) → Cr²⁺(aq) + 2Cl⁻(aq).

Energy (the lattice energy) is required to pull apart the oppositely charged ions in chromium chloride.

The heat of hydration is liberated energy when the separated ions (in this example chromium cations and chlorine anions) attract polar water molecules.

Because the lattice energy is higher than the heat of the hydration (endothermic reaction), we can conclude that bonds between ions are strong (the electrostatic attraction between oppositely charged ions).

3 0
3 years ago
Read 2 more answers
Nitrogen and hydrogen combine to form ammonia in the Haber process. Calculate (in kJ) the standard enthalpy change ∆H° for the r
Kazeer [188]

Answer:

∆H° rxn = - 93 kJ

Explanation:

Recall that a change in standard in enthalpy, ∆H°, can be calculated from the inventory of the energies, H, of the bonds  broken minus bonds formed (H according to Hess Law.

We need to find in an appropiate reference table the bond energies for all the species in the reactions and then compute the result.

              N₂ (g)   +            3H₂ (g)   ⇒                          2NH₃ (g)

1 N≡N = 1(945 kJ/mol)     3 H-H = 3 (432 kJ/mol)       6 N-H = 6 ( 389 kJ/mol)

∆H° rxn = ∑  H bonds broken  - ∑ H bonds formed

∆H° rxn = [ 1(945 kJ)   + 3 (432 kJ) ] - [ 6 (389 k J]

∆H° rxn = 2,241 kJ -2334 kJ = -93 kJ

be careful when reading values from the reference table since you will find listed N-N bond energy (single bond), but we have instead a triple bond,  N≡N,  we have to use this one .

8 0
3 years ago
Which is the most accurate description of compounds?
baherus [9]

Answer: c.They have a unique set of properties that can be used as identifiers.

Explanation:

Compound is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass.

Compounds can be decomposed into simpler constituents using chemical reactions.

Example: Water (H_2O)

2H_2O\rightarrow 2H_2+O_2

Compounds have different properties than the elements it is made up of.

Thus the most accurate description of compounds is that they have a unique set of properties that can be used as identifiers.

3 0
3 years ago
What is the definition of Amplitude?
katen-ka-za [31]

Answer:

the maximum extent of a vibration or oscillation, measured from the position of equilibrium.

Explanation:physics

4 0
3 years ago
The shielding of electrons gives rise to an effective nuclear charge, Zeff, which explains why boron is larger than oxygen. Esti
Vesna [10]

Zeff = Z - S

Here, Z is the number of protons in the nucleus, that is, atomic number, and S is the number of nonvalence electrons.

For boron, the electronic configuration is 1s₂ 2s₂ 2p₄

Z = 5, S = 2

Zeff = 5-2 = +3

For O, electronic configuration is 1s₂ 2s₂ 2p₄

Z = 8, S = 2

Zeff = 8-2 = +6

Hence, the correct answer is second option, that is, +3 and +6, the Zeff of boron is smaller in comparison to O, thus, boron exhibits a bigger size than O.

3 0
3 years ago
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