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Mamont248 [21]
3 years ago
13

Charlie bought 16 cartons of ice cream and 7 cartons of yogurt. Each carton of ice cream cost $6 and each carton of yogurt cost

$1. How much more did Charlie spend on ice cream than on yogurt?
Mathematics
2 answers:
pochemuha3 years ago
6 0
$89 because 16 x 6 = $96 and 7 x 1 = $7.     96 - 7 = $89.

lys-0071 [83]3 years ago
4 0
Charlie spent $89 more dollars on ice cream than on yogurt. He spent a total of $96 on ice cream and $7 on yogurt. If you subtract 7 from 96 you get 89. 
$96- $7= $89
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Please help me (9-7×3+4)^2
kherson [118]
(9 - 7 × 3 + 4)²
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5 0
4 years ago
Pls answer fast my teacher is waiting!
a_sh-v [17]

Answer:

For company A, y = 24x + 42

For company B, y = 28x + 25

Step-by-step explanation:

x is the number of containers

y is the total cost

For company A, y = 24x + 42

For company B, y = 28x + 25

For the cost of both companies to be the same, then

24x + 42 = 28x + 25

28x - 24x = 42 - 25

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Mr Lycan would have to order about 4 containers so the cost would be the same from each company

4 0
3 years ago
Please answer them! be quick if you can, thank you.
fiasKO [112]

Answer:

Question one = 35a - 15

Question two = 9

Step-by-step explanation:

Distributive property means to multiply all the numbers inside the parenthesis

by the outside number. 5 x 7a equals 35a and 5 x 3 = 15.

35 x 9 - 315 - 15 = 300

A = 9

5 0
3 years ago
Find the number of ways of arranging the numbers
Doss [256]

First of all, note that all integers are either 0,1, or 2 modulo 3 (if you're not familiar with this terminology, it means that every integer is either a multiple of 3, or it is 1 or 2 away from a multiple of 3).

So, we can think of our numbers as

\begin{array}{c|c}x&x\mod 3\\0&0\\1&1\\2&2\\3&0\\4&1\\5&2\\6&0\\7&1\\8&2\\9&0\end{array}

In order to make sure that the sum of any three adjacent numbers is divisible by 3, we have to make sure that any group of 3 three adjacent numbers contains a 0, a 1 and a 2. This is possible only if we arrange our 9 numbers in 3 groups of 3 numbers containing 0,1 and 2 exactly once, repeating always the same pattern.

For example, we could arrange our numbers following the pattern

0,1,2,0,1,2,0,1,2

or

2,0,1,2,0,1,2,0,1

We have 3!=6 possible patterns. Suppose for example that we choose the pattern

0,1,2,0,1,2,0,1,2

One possible way of following this pattern would be the arrangement

3,1,2,6,4,5,9,7,8

In fact, we substituted every '0' with a multiple of 3 (3, 6 or 9), every '1' with a number 1 away from a multiple of 3 (1, 4 or 7) and every '2' with a number 2 away from a multiple of 3 (2, 5 or 8).

This means that, once we fix a patter, we have 3 choices for the first 3 slots, 2 choices for the next 3 slots, and the final slot will be fixed. So, we have

3\cdot 3\cdot 3\cdot 2 \cdot 2 \cdot 2 = 216

possible ways of following a fixed pattern. Since the number of patterns was 6, we have

216\cdot 6 = 1296

possible arrangements.

7 0
3 years ago
Read 2 more answers
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