Answer:
m∠CAO=8º
m∠SAC=82º
Step-by-step explanation:
We know that m∠OAS is 90º because it is a radius to a tangent. This will be useful later.
OA=OB because they are both radii. If we draw a line from A to B, this makes an isosceles triangle ABO with a vertex angle of 32 because of the central angle theorem. This means that m∠OAB and m∠OBA are both 74º.
Isosceles triangle CAB is also formed with the construction of AB. Using the inscribed angle theorem, we can find ACB, which is 16º. Solve for the other angles and you get 82º. To find m∠CAO, subtract m∠OAB from m∠CAB, and this returns 8.
To find m∠SAC, subtract m∠CAO from m∠OAS, which is 90º-8º, and you get 82º.
The answer is Cu = X times 2.5
Answer:

Step-by-step explanation:
6^4/6^1
6^(4-1)
=6^3
You gave little context, so here is a few solutions.
POSSIBLE #1:
assuming s is a variable
---> Simplify
×
to 

---> Collect like terms.

---> Simplify.

POSSIBLE #2: (assuming s is not relevant)
Simplifying
4x + -12 = 16 + 8x
Reorder the terms:
-12 + 4x = 16 + 8x
Solving
-12 + 4x = 16 + 8x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-8x' to each side of the equation.
-12 + 4x + -8x = 16 + 8x + -8x
Combine like terms: 4x + -8x = -4x
-12 + -4x = 16 + 8x + -8x
Combine like terms: 8x + -8x = 0
-12 + -4x = 16 + 0
-12 + -4x = 16
Add '12' to each side of the equation.
-12 + 12 + -4x = 16 + 12
Combine like terms: -12 + 12 = 0
0 + -4x = 16 + 12
-4x = 16 + 12
Combine like terms: 16 + 12 = 28
-4x = 28
Divide each side by '-4'.
x = -7
Simplifying
x = -7
If there are any other ways to solve this please add more context in the comments below this answer! Hope this was helpful! Have a marvelous day/night!
Answer:
idk
Step-by-step explanation: