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3 years ago

Lucy went to Chik Fil A. She bought a meal that cost $9.27. If the tax rate is 6% how

Mathematics

1 answer:

borishaifa [10]3 years ago

4 0

Answer:

$9.83

Step-by-step explanation:

Tax= 6% of 9.27

$=\frac{6}{100}*9.27\\\\=\frac{55.62}{100}\\\\=0.5562$

Amount paid by her = 9.27 + 0.5562 = 9.8262 = $9.83

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Bella wants to tile a wall measuring 1.2 m by 2.16 m. She finds square tiles she likes with side lengths of 10 cm, 12 cm or 18 c

uysha [10]

Answer:

Step-by-step explanation:

1.2m = 120 cm

2.16 m = 216cm

120×216 =25920cm

2) 10×18 = 180

25920/180= 144

√144 = 12

8 0

2 years ago

The student council wants to rent a ballroom for the junior prom. The ballroom's rental rate is $1500 for 3h and $125 for each a

Tems11 [23]

They can afford only 5 1/2 hours

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3 years ago

In a population of grasshoppers, the ratio of grasshoppers with a white marking to those without a white marking is 2:3. An ento

LekaFEV [45]

Answer:

D. 116

Step-by-step explanation:

Let the grasshoppers with a white marking be 2x.

Let the grasshoppers without a white marking be 3x.

2x + 3x = 290

5x = 290

x = 290 / 5

x = 58

The grasshoppers with a white marking

= 2x

= 2 ( 58 )

= 116

3 0

3 years ago

In Vancouver, British Columbia, the probability of rain during a winter day is 0.42, for a spring day is 0.23, for a summer day

nadezda [96]

Answer:

31.82% probability that this day would be a winter day

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening

In this question:

Event A: Rain

Event B: Winter day

Probability of rain:

0.42 of 0.25(winter), 0.23 of 0.25(spring), 0.16 of 0.25(summer) or 0.51 of 0.25(fall).

$P(A) = 0.42*0.25 + 0.23*0.25 + 0.16*0.25 + 0.51*0.25 = 0.33$

Intersection:

Rain on a winter day, which is 0.42 of 0.25. So

$P(A \cap B) = 0.42*0.25 = 0.105$

If you were told that on a particular day it was raining in Vancouver, what would be the probability that this day would be a winter day?

$P(B|A) = \frac{0.105}{0.33} = 0.3182$

31.82% probability that this day would be a winter day

6 0

3 years ago

Roderick is counting the change on his dresser. he has twice as many pennies as he does dimes. he has twice the amount of dimes

melamori03 [73]

P = 2d
d = 2n.....n = 1/2d
q = d - 3

since dimes is mentioned in relation to quarters, pennies, and the nickels, u would use d as ur variable

ur expression would be : d + (2d) + (1/2d) + (d - 3) = total amount of coins...then u would solve for d, the number of dimes. And once u know that, u can sub that answer back into ur original equations to find the number of pennies, quarters and nickels

8 0

3 years ago