Answer is 9/5
You can count the rise/run on the graph or use slope formula (y2-y1) over (x2 -x1)
5-(-4) over 3-(-2) = 9/5
Answer:
There are 10 possible ways the student can schedule the three classes
Step-by-step explanation:
The college student is choosing 3 classes to take during the first, second, and third semester from 5 electives.
Therefore, the student is choosing 3 items from a total of 5 and the order is not of key concern here. This is thus a combination problem;
5C3 = 10
read as 5 choose 3
The above mathematical operation can be performed using any modern calculator.
Looks like all real numbers except 1. It touch's all the y except 1 aka range
