The dimensions and volume of the largest box formed by the 18 in. by 35 in. cardboard are;
- Width ≈ 8.89 in., length ≈ 24.89 in., height ≈ 4.55 in.
- Maximum volume of the box is approximately 1048.6 in.³
<h3>How can the dimensions and volume of the box be calculated?</h3>
The given dimensions of the cardboard are;
Width = 18 inches
Length = 35 inches
Let <em>x </em>represent the side lengths of the cut squares, we have;
Width of the box formed = 18 - 2•x
Length of the box = 35 - 2•x
Height of the box = x
Volume, <em>V</em>, of the box is therefore;
V = (18 - 2•x) × (35 - 2•x) × x = 4•x³ - 106•x² + 630•x
By differentiation, at the extreme locations, we have;
Which gives;
6•x² - 106•x + 315 = 0
Therefore;
x ≈ 4.55, or x ≈ -5.55
When x ≈ 4.55, we have;
V = 4•x³ - 106•x² + 630•x
Which gives;
V ≈ 1048.6
When x ≈ -5.55, we have;
V ≈ -7450.8
The dimensions of the box that gives the maximum volume are therefore;
- Width ≈ 18 - 2×4.55 in. = 8.89 in.
- Length of the box ≈ 35 - 2×4.55 in. = 24.89 in.
- The maximum volume of the box, <em>V </em><em> </em>≈ 1048.6 in.³
Learn more about differentiation and integration here:
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Answer:
The price of hot dog is $2.5 and that of a pretzel is $1.25.
Step-by-step explanation:
Let the cost of hotdogs be x and that of pretzels be x.
So,
4x+3y = 13.75 ...(1)
and
2x+5y = 11.25 ...(2)
Multiply equation (2) by 2.
4x+10y = 22.5 ...(3)
Subtract equation (1) from (3).
4x+10y-(4x+3y) = 22.5-13.75
4x+10y-4x-3y = 8.75
7y = 8.75
y = 1.25
Put the value of y in equation (1).
4x+3(1.25) = 13.75
4x+3.75 = 13.75
4x = 13.75-3.75
4x = 10
x = 2.5
So, the price of hot dog is $2.5 and that of a pretzel is $1.25.
I have mercy:
8x and 9x+5 (the angles) form a right angle so 8x+9x+5=90 which means x is 5 and plugging it back into the angles 8x we get 40 sinceBHR and angle 8x are vertical angles they are equal to each other and so it's equal to 40
Answer:
Step-by-step explanation:
<u>Step 1: Subtract m from both sides
</u>
<u>Step 2: Divide both sides by -1
</u>
Answer:
Answer:
A. Rectangle
Step-by-step explanation:
It is often useful to plot the given points on a graph. Doing that lets you see the figure is a rectangle. You can count grid squares to see that the distances are the same between the endpoints of opposite sides.
