5,3..........................................
Answer:
Yes.(16.088m combined jump)
Step-by-step explanation:
Combining jumps=4.76+5.428+5.9=16.088
16.088>16
Therefore Juan qualified for the competition
Answe
Given,
f(x) = 49 − x² from x = 1 to x = 7
n = 4
For x= 1
f(x₀) = 49 - 1^2 = 48
x = 2.5
f(x₁) = 42.75
x = 4
f(x₂) = 49 - 4^2 = 33
x = 5.5
f(x₃) = 49 - 5.5^2 = 18.75
x = 7
f(x₄) = 49 - 7^2 = 0
We have to evaluate the function on therigh hand point
![A = \Delta x [f(x_1)+f(x_2)+f(x_3)+f(x_4)]](https://tex.z-dn.net/?f=A%20%3D%20%5CDelta%20x%20%5Bf%28x_1%29%2Bf%28x_2%29%2Bf%28x_3%29%2Bf%28x_4%29%5D)
![A = 1.5 [42.75+33+18.75+0]](https://tex.z-dn.net/?f=A%20%3D%201.5%20%5B42.75%2B33%2B18.75%2B0%5D)
For Area for left hand sum
![A = \Delta x [f(x_0)+f(x_1)+f(x_2)+f(x_3)]](https://tex.z-dn.net/?f=A%20%3D%20%5CDelta%20x%20%5Bf%28x_0%29%2Bf%28x_1%29%2Bf%28x_2%29%2Bf%28x_3%29%5D)
![A = 1.5 [48+42.75+33+18.75]](https://tex.z-dn.net/?f=A%20%3D%201.5%20%5B48%2B42.75%2B33%2B18.75%5D)
i think it is 803.6 i tried i think so that it the answer
Answer:
C. 4(cos(300°) +i·sin(300°))
Step-by-step explanation:
The magnitude will be ...
magnitude = √(2^2 +(-2√3)^2) = √(4+12) = 4
The negative imaginary part puts the angle in the 4th quadrant. The answer choice with a magnitude of 4 and a 4th-quadrant angle is ...
4(cos(300°) +i·sin(300°))
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If you want to figure the angle, it will be ...
angle = arctan(Im()/Re()) = arctan(-2√3/2) = arctan(-√3) = -60°
The corresponding 4th-quadrant angle is 300°.
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<em>Comment on answer choices</em>
Answer choice A is <em>another representation of the same number</em>. Typically, we want the magnitude to be positive in polar form, so that answer can be avoided on those grounds.
