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velikii [3]
3 years ago
10

What is the coefficient of the third term of the trinomial? (In other words, what is C?)

Mathematics
1 answer:
AysviL [449]3 years ago
7 0
-3 because 3 times -1 is -3
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Amy is solving the equation using the steps shown.
Delicious77 [7]

The correct next step Amy could take is to factor (x^2 - 16) on the left side of the equation to yield (x + 4)(x – 4)(x + 2) = 0.

The equation is given as:

\mathbf{(x^2 - 16)(x + 2) = 0}

The possible next steps are:

1. Expand the equation as follows

\mathbf{x^3+2x^2-16x-32 = 0}

2. Express x^2 -16 as a difference of two squares as follows

\mathbf{(x + 4)(x- 4)(x + 2) = 0}

However, the correct step in this case is to factor x^2 - 16 as a difference of two squares to give \mathbf{(x + 4)(x- 4)(x + 2) = 0}

This is so, because the question says Amy is trying to solve for variable x.

This step will ensure that she gets the possible values of x, unlike expanding the whole equation .

Hence, the correct next step is \mathbf{(x + 4)(x- 4)(x + 2) = 0}

Read more about equations at:

brainly.com/question/7674413

7 0
2 years ago
What is the surface area of the triangular prism represented by the net below?
abruzzese [7]
There isnt a image of the shape
7 0
3 years ago
What is the distance from the origin to point A graphed on the complex plane below?
Degger [83]

Answer: False

Step-by-step explanation:

You didn't give the coordinate plane that I was supposed to use while helping you.

3 0
3 years ago
Which statement is most likely to be true for this distribution
andreyandreev [35.5K]

Answer:

the mean is greater than the median

5 0
3 years ago
Read 2 more answers
What is thr inverse of f(x) if the function is x=-4,-2,0,2,4 f(x)=-2,-1,0,1,2
Lorico [155]
For a function, if it has an inverse function, keep in mind that, the "domain of the original, is the range of the inverse, and the range of the original, is the domain of the inverse", what the dickens does that mean?

well, it means the values for "x" and f(x), on the inverse, are the same values, but swapped up, therefore

\bf \stackrel{original~function}{\begin{array}{ccll}
x&f(x)\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
-4&-2\\
-2&-1\\
0&0\\
2&1\\
4&2
\end{array}}\qquad \qquad \qquad 
\stackrel{inverse~function}{\begin{array}{ccll}
x&f(x)\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
-2&-4\\
-1&-2\\
0&0\\
1&2\\
2&4
\end{array}}
7 0
3 years ago
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