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3 years ago

The staff at a company went from 40 to 29 employees. what is the percent decrease in staff

1 answer:

5 0

Number of employees outside of company=40-29=11

we can calculate the percent decrease in staff by the rule of 3

40 employees-----------------100%
11 employees---------------- x

x=(11 employees*100%) / 40 employees=27.5%

The percent decrease in staff was: 27.5%

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The measure of each interior angle of a regular polygon is 150 how many sides does the polygon have?

Dmitry [639]

The exterior and an interior angles always add up to 180 degrees.
180-150=One exterior angle
180-150=30
We know that all of the exterior angles add up to 360
360/30= the number of sides
360/30=12
The shape has 12 sides.

3 0

3 years ago

I NEED HELP PLEASE! If you can help me with this you amazing! Thank you

krek1111 [17]

Answer:

$a=-3$

Step-by-step explanation:

we have

$a-2=\frac{3+6a}{3}$

Solve for a

That means ----> Isolate the variable a

Factor 3 in the numerator right side

$a-2=\frac{3(1+2a)}{3}$

Simplify right side

$a-2=1+2a$

subtract a both sides

$a-2-a=1+2a-a$

$-2=1+a$

subtract 1 both sides

$-2-1=1+a-1$

$-3=a$

Rewrite

$a=-3$

6 0

2 years ago

Factor. Explain. 24x³y²-4x²y+84x^4

Elan Coil [88]

Answer:

$\boxed{\bold{4x^2\left(6xy^2-y+21x^2\right)}}$

Step By Step Explanation:

Apply Exponent Rule $\bold{\:a^{b+c}=a^ba^c}$

$\bold{x^4=x^2x^2,\:x^3y^2=x^2x}$

$\bold{24x^2x-4x^2y+84x^2x^2}$

Rewrite 84: $\bold{21\cdot \:4}$

Rewrite 24: $\bold{6\cdot \:4}$

$\bold{6\cdot \:4x^2x-4x^2y+21\cdot \:4x^2x^2}$

Factor Out Common Term $\bold{4x^2}$

$\bold{4x^2\left(6xy^2-y+21x^2\right)}$

➤ $\boxed{\bold{Mordancy}}$

6 0

2 years ago

20 Points! Solve for x

Marrrta [24]

Answer:

so all x's have to be added together.

8x+5x+10x+7x=30x

-2+3=1

1dividedby30=30

x=30

hope this helps

7 0

2 years ago

Read 2 more answers

Find all of the points of the form (x −1) which are 4 unit from the point (3,2)

Bond [772]

Answer:

$(3+2\sqrt{2},2+2\sqrt{2}),(3-2\sqrt{2},2-2\sqrt{2})$

Step-by-step explanation:

$Points\ are\ of\ the\ form\ (x,x-1)\\\\Distance\ of\ these\ points\ from\ (3,2)=4\\\\\sqrt{(x-3)^2+(x-3)^2}=4\\\\\sqrt{(x-3)^2+(x-1-2)^2}=4\\\\\sqrt{2(x-3)^2}=4\\\\2(x-3)^2=16\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ square\ both\ the\ sides\\\\(x-3)^2=\frac{16}{2}\\\\(x-3)^2=8\\\\(x-3)=\pm 2\sqrt{2}\ \ \ \ \ \ \ \ \ \ \ square\ root\ both\ the\ sides\\\\x=3\pm 2\sqrt{2}\\\\When\ x=3+2\sqrt{2}\ \ \Rightarrow x-1=3+2\sqrt{2}-1=2+2\sqrt{2}\\\\When\ x=3-2\sqrt{2}\ \ \Rightarrow x-1=3-2\sqrt{2}-1=2-2\sqrt{2}$

4 0

2 years ago