What is G equivalent to in 21.8-G=9.5???

Mathematics

2 answers:

inn [45]2 years ago

7 0

G is equal 12.3 in this equation

Mamont248 [21]2 years ago

6 0

Start with the equation then subtract 21. 8 from both sides. u get -G= -12.3 then divide both sides by -1 and you get G-12.3

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What is a solution for 11/12

elena-s [515]

Answer:

It is either 11/12 or 0.91666666667.....

Step-by-step explanation:

Because this can not be actually divided into a "number" like 2 or 5, we can only get a approximate. Like the top answer.

Round to the nearest ten is 0.9

Round it to nearest hundredths is 0.92

7 0

2 years ago

Find the radius of convergence, r, of the series. ? n2xn 7 · 14 · 21 · ? · (7n) n = 1

defon

I'm guessing the series is supposed to be

$\displaystyle\sum_{n=1}^\infty\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}$

By the ratio test, the series converges if the following limit is less than 1.

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7\cdot14\cdot21\cdot\cdots\cdot(7n)\cdot(7(n+1))}}{\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}}\right|$

The first $n$ terms in the numerator's denominator cancel with the denominator's denominator:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7(n+1)}}{n^2x^n}\right|$

$|x^n|$ also cancels out and the remaining factor of $|x|$ can be pulled out of the limit (as it doesn't depend on $n$ ).

$\displaystyle|x|\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2}{7(n+1)}}{n^2}\right|=|x|\lim_{n\to\infty}\frac{|n+1|}{7n^2}=0$

which means the series converges everywhere (independently of $x$ ), and so the radius of convergence is infinite.