The initial membership fee before any months are considered is 35.
Substitute 0 with x because no months have been considered. Like what was previously said, y is the total cost, so:
Y=12(0)+35
12 x 0 = 0
Y=0+35
Y=35
For the given system of inequalities, x represents the number of brownies and y the number of cookies.
And the graph can be seen in the image below.
<h3>What each variable represents?</h3>
Here we have the system of inequalities:
4x + 6y ≥ 200
x + y < 75.
We know that they want to make less than 75 items, that is what the second inequality:
x + y < 75.
Represents.
We also know that each brownie costs $4, and each cookie costs $6, then the expression:
x*4 + y*6
Represents the revenue for selling x brownies and y cookies, and because they want to earn at least $200, the inequality becomes:
x*4 + y*6 ≥ 200
So we conclude that x represents the number of brownies and y the number of cookies.
Now the system is:
4x + 6y ≥ 200
x + y < 75.
To graph it, you just need to graph both the lines and shade the indicated region, we can write the inequalities sa:
y ≥ (200 - 4x)/6
y < 75 + x
Just graph these two lines, for the first one you need to use a solid line and shade the region above the line, for the second, a dashed line and you need to shade the region below the line. The graph can be seen below.
The solutions to the systems are in the region where both shaded parts intersect.
There we can see that the point x = 20 and y = 20 (among a lot of other ones) is a solution to the system.
If you want to learn more about systems of inequalities:
brainly.com/question/9774970
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The number of mole of pure 11C (carbon-11) initially present is 0.2727 mole
<h3>Description of mole </h3>
The mole of a substance is related to it's mass and molar mass according to the following equation
Mole = mass / molar mass
With the above formula, we can obtain the number of mole of pure 11C. Detail below:
<h3>How to determine the mole of 11C</h3>
From the question given, the following data were obtained:
- Molar mass of 11C = 11 g/mol
- Mass of 11C = 3 g
- Mole of 11C =?
Mole = mass / molar mass
Mole = 3 / 11
Mole = 0.2727 mole
Therefore, the number of mole of pure 11C initially present is 0.2727 mole
Learn more about mole:
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