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Marta_Voda [28]
3 years ago
5

Find the value of z in the figure below..​

Mathematics
1 answer:
zzz [600]3 years ago
3 0

answer

z = 100

opposite angles

when inscribed in a circle, the opposite angles of a quadrilateral add up to 180

so z + 80 = 180 and y + 120 = 180

solve for z

z + 80 = 180

z = 180 - 80

z = 100

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Mr. Wu rides his bike at 6 mph to the bus station. He then rides the bus to work, averaging 30 mph.
pshichka [43]

Answer:

26 mi

Step-by-step explanation:

Convert 20 min to hrs: 20/60 = 1/3 hr

:

Let t = time on the bike

then

t-(1/3) = time on the bus

:

Write a dist equation Dist = speed * time:

:

Bike dist + bus dist = 26 mi

 

6t + 30[t-(1/3)] = 26

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6t + 30t - 10 = 26

36t = 26 + 10

36t = 36

t = 1 hr on the bike

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6 mph for 1 h = 6 mi from house to the bus station

:

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Check solution by finding the distance

6(1) + 30(2/3) =

6 + 20 = 26 mi

5 0
2 years ago
Find the missing probability. P(A)=720,P(B)=35,P(A∩B)=21100 ,P(A∪B)=?
AlladinOne [14]

P( A U B) = 37/50

Step-by-step explanation:

7/20+3/5+21/100

IF YOU NEED MORE HELP LMK

If you can please mark this as the brainliest

8 0
3 years ago
The table shows the cost, C, in dollars, to rent a car from Carl's Car Rentals. Determine the following: a) What is the fixed co
zubka84 [21]

Answer:

a) Fixed cost = $50

b) Total variable cost is $15, while variable cost per unit is $0.15.

c) C = 50 + d0.15

d) Direct variation

e) The cost of renting a car for a day and driving a total of 800km is $170,

Step-by-step explanation:

a) What is the fixed cost?

Fixed cost is a cost that does not change with the level of activity. Fixed is incurred whether there is an activity, or there is no activity at all, that is, when the activity is zero.

Since cost, C, is equal to $50 when distance, d (km), is equal to zero in the table, the fixed cost is therefore equal to $50, i.e.:

Fixed cost = $50

b) What is the variable cost?

Variable cost is a cost that changes as the level of activity changes. From the table, the variable cost can be obtained by deducting the fixed cost from the total cost. This can be calculated using any of the distance, d (km), in the table.

Using the distance of 100 as an example, the total variable cost can be obtained as follows:

Variable cost = Total Cost at 100 distance - Fixed cost = $65 - $50 = $15

Note that variable cost per distance at 100 distance can be obtained as follows:

Variable cost per distance = $15 / 100 = $0.15

c) Write an equation relating your answer from part (a) and part (b)

Since,

C = Cost

d = distance (km)

Fixed cost = $50

Variable cost per distance = $0.15

Therefore, suppressing the dollar sign for simplicity purpose, an equation relating the above can be given as follows:

C = 50 + d0.15 ............................................. (1)

d) What kind of variation is this relationship showing?

This is a <u>direct variation</u>.

Direct variation is a variation in which an increase in one variable will lead to an increase in another variable.

For example in equation (1), a increase in d which is multiplied by $0.15 will lead to an increase in C.

e) Calculate the cost of renting a car for a day and driving a total of 800km.

This implies that d = 800.

Substituting d = 800 into equation (1), we have:

C = 50 + (800 * 0.15) = 170

Therefore, the cost of renting a car for a day and driving a total of 800km is $170.

6 0
3 years ago
A local library shows movies on Thursday evenings. The library administrator has chosen the next six movies he will show, but he
DENIUS [597]
There are 6 choices for the first movie. Having chosen the first movie there are 5 choices for the second, 4 choices for the third, 3 for the fourth, 2 for the fifth and 1 for the last. Therefore the number of possible offerings is:
6\times5\times4\times3\times2\times1=720
The answer is 720.
8 0
3 years ago
Chloe needed to get her computer fixed. She took it to the repair store. The technician at the store worked on the computer for
yawa3891 [41]
389.50 minus 197 for parts will give you your answer
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3 years ago
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