How do you solve this problem and what is the equation 3x(8-3) (6 4)/2?

Mathematics

2 answers:

dezoksy [38]3 years ago

7 0

Answer:

C:\Users\dorie\AppData\Local\Temp\PRODUCT_NAME_UNKNOWN_CrashDumpPRODUCT_VERSION_MAJOR_UNKNOWN-PRODUCT_VERSION_MINOR_UNKNOWN-2019-09-24--10-44-23_.dmp

Charra [1.4K]3 years ago

4 0

To solve the problem, do the problem in the parenthesis () then do your answer with the numbers outside the ().

(8-3) = 5 x 3 = 15

(6 + 4) = 10 / 2 = 5

(6 - 4) = 2 / 2 = 1

(6 x 4) = 24 / 2 = 3

Um... part of the (6 4) doesn't make sense... What goes between the numbers? Plus, minus, multiply or division sign? Please tell.

But, I already got you started off and I'll let you figure out the rest. (If you can not figure out the rest, please tell me what sign is between the 6 and 4 in (6 4) and then I'll give you the answer and a better explanation.)

I hope this helps! :D

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3 years ago

A storage tank will have a circular base of radius r and a height of r. The tank can be either cylindrical or hemispherical (ha

Neko [114]

Answer:

Volume: $\frac{2}{3}\pi r^3$

Ratio: $\frac{2}{9}r$

Step-by-step explanation:

First of all, we need to find the volume of the hemispherical tank.

The volume of a sphere is given by:

$V=\frac{4}{3}\pi r^3$

where

r is the radius of the sphere

V is the volume

Here, we have a hemispherical tank: a hemisphere is exactly a sphere cut in a half, so its volume is half that of the sphere:

$V'=\frac{V}{2}=\frac{\frac{4}{3}\pi r^3}{2}=\frac{2}{3}\pi r^3$

Now we want to find the ratio between the volume of the hemisphere and its surface area.

The surface area of a sphere is

$A=4 \pi r^2$

For a hemisphere, the area of the curved part of the surface is therefore half of this value, so $2\pi r^2$ . Moreover, we have to add the surface of the base, which is $\pi r^2$ . So the total surface area of the hemispherical tank is