tenth place: 18.2
hundredth place: 18.19
one place: 18
tens place: 20
hundred place: 0
I didn't know which one you needed so I did a bunch
Answer:
Step-by-step explanation:
12=3x-2y
2y+12=3x
2y=3x-12
y=(3x-12)/2
y=mx+b
To be parallel to the line above our line must have the same slope or m. The above line has a slope of 3/2 or 1.5 so the parallel line will be
y=1.5x+b, using point (7,10) we can solve for the y intercept or b
10=1.5(7)+b
10=10.5+b
b=-0.5 so our line is
y=1.5x-0.5
Answer:



<h3>-----------------------</h3><h3>hope it helps...</h3><h3>have a great day!!</h3>
Answer:
In order to find the variance we need to calculate first the second moment given by:
And the variance is given by:
![Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20%2B%5BE%28X%29%5D%5E2%20%3D%2023.36%20-%5B4.74%5D%5E2%20%3D%200.8924)
And the deviation would be:

Step-by-step explanation:
Previous concepts
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).
Solution to the problem
For this case we have the following distribution given:
X 3 4 5 6
P(X) 0.07 0.4 0.25 0.28
We can calculate the mean with the following formula:

In order to find the variance we need to calculate first the second moment given by:

And the variance is given by:
![Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20%2B%5BE%28X%29%5D%5E2%20%3D%2023.36%20-%5B4.74%5D%5E2%20%3D%200.8924)
And the deviation would be:

ANSWER
The number of children between the ages of 9 and 15 who visited the park is

EXPLANATION
The number of children between the ages of 9 and 15 who visited the park are those within the age group 9 to 12 and 12 to 15.
We can from the graph that, the height of the bar that corresponds to the age group 9 to 12

and the height of the bar that corresponds to the age group 12 to 15

The sum of the two frequencies