Radius OA of circle O has a slope of 2.5. What is the slope of the line tangent to circle O to point A?

2 answers:

5 0

The tangent at A is perpendicular to OA, so has a slope that is the negative reciprocal of that of the radius: -1/2.5 = -2/5.

Mekhanik [1.2K]3 years ago

4 0

Answer: The required slope of the line tangent to the circle at point A is -0.4.

Step-by-step explanation: Given that the radius OA of a circle with center O has a slope of 2.5.

We are to find the slope of the line tangent to the circle at the point A.

We know that

The radius of a circle at a point on the circumference of a circle is perpendicular to the tangent line at the same point on the circumference of the circle.

Also, the product of the slopes of two perpendicular lines is -1.

So, if m is the slope of the tangent line at the point A, then we must have

$m\times 2.5=-1\\\\\Rightarrow m=-\dfrac{1}{2.5}\\\\\\\Rightarrow m=-\dfrac{10}{25}\\\\\Rightarrow m=-\dfrac{2}{5}\\\\\Rightarrow m=-0.4.$

Thus, the required slope of the line tangent to the circle at point A is -0.4.

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Step-by-step explanation:

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Please help with this

lana66690 [7]

Alright, let's convert to decimals for these calculations: fractions could get messy.
1/5 = .2
1/2 = .5

Imagine a rectangular solid in your mind. How many sides does it have?
6. In the image shown you have 3 facing you. In addition to those, there are 3 not shown. They will correspond to the calculations you make on the front, though, so all you have to do is double the values you get.

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A = 5 (width) * 4.5 (height) for the right face of the rectangular solid (and the one on the left, away from you.)
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Calculating these values, we get that
A=14.4
A=22.5
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So that's 3 out of 6 values for the full surface area.
Like I said though, these values can merely be doubled for the complete area.
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