Basically, we need to plug in the given values for the variables 
and 
into the given expression 
. First off, we can plug in all the given values into the expression, giving us 
. Now, perform the operations on the inside of the parentheses. Doing this, we get 
. Now, we use the distributive property to simplify. This gives us 
. Finally, when we add the two numbers, we get 
. Hope this helped!
Radius OA of circle O has a slope of 2.5. What is the slope of the line tangent to circle O to point A?
2 answers:
Answer: The required slope of the line tangent to the circle at point A is -0.4.
Step-by-step explanation: Given that the radius OA of a circle with center O has a slope of 2.5.
We are to find the slope of the line tangent to the circle at the point A.
We know that
The radius of a circle at a point on the circumference of a circle is perpendicular to the tangent line at the same point on the circumference of the circle.
Also, the product of the slopes of two perpendicular lines is -1.
So, if m is the slope of the tangent line at the point A, then we must have
Thus, the required slope of the line tangent to the circle at point A is -0.4.
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