Question

1 thanks for your help!

Answer 1

Answer:

Solution is

$(\frac{1}{2},\frac{-3}{2})$

Which is Option C

Step-by-step explanation:

We are given the equations

4x - 6y = 11                     ...............(i)

3x+y = 0                         ..............(ii)

Now from equation (ii) we have

3x + y = 0

subtracting 3x from both sides we get

3x + y - 3x = 0 - 3x

y = -3x                       ....................(iii)

substituting this value in equation (i) which is

4x - 6y =11

Putting the value of y

4x - 6(-3x) = 11

4x + 18x = 11

22x = 11

Dividing both sides by 22

we get

$\frac{22x}{22}=\frac{11}{22}$

or

x=$\frac{1}{2}$

Now we have equation (iii) which tells us that

y= -3x

Putting value of x here

y = -3($\frac{1}{2}$)

It becomes

y = $\frac{-3}{2}$

So

Solution set of the equation is

$(\frac{1}{2},\frac{-3}{2})$