The correct answer is {1, 2, 5, 6}.
A intersect B would be {3, 4}; the complement of this is everything else.
Answer:
please where is the diagram
Answer:
The answer is in the the attachment
Step-by-step explanation:
The question you posted was incomplete but i believe below is the complete question;
Let P2 denote the vector space of all polynomials with degree less than or equal to 2. (
a) Show that B = {1 + x + x 2 , 1 + 2x − x 2 , 1 − 2x − x 2} is a basis for P2.
(b) Find the coordinate vector of p(x) = 1 + 2x + 3x 2 relative to the basis B
The answer is explained in the attachments.
Answer:
x^35
Explanation:
5 x 7 = 35
Answer:
y=12.75x and y=13x
Step-by-step explanation:
The rate of change is another name for slope. To find the slope of Relationship B, we use the formula
m = \frac{y_2-y_1}{x_2-x_1}
Using the first two points, we have
m = (50-25)/(4-2) = 25/2 = 12.5
This means that anything with a rate of change greater than 12.5 works in this problem.
The equations listed for Relationship A are in slope-intercept form, y=mx+b, where m is the slope and b is the y-intercept (in all of these, b = 0).
In the first equation, m = 13; in the second equation, m = 11.5; in the third equation, m = 12.75; and in the fourth equation, m = 12.25. The only ones with higher slopes than Relationship B are the first and the third one.
