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kap26 [50]
3 years ago
9

Solve for x: 12-2x=-2(y-x)

Mathematics
1 answer:
a_sh-v [17]3 years ago
3 0
12 - 2x = -2(y - x)

12 - 2x = -2y - (-2x)

12 - 2x = -2y + 2x

12 - 2x - 2x = -2y + 2x - 2x

12 - 4x = -2y

12 - 12 - 4x = -2y - 12

-4x = -2y - 12

-4x/4 = -2y/4 - 12/4

-x = -0.5y - 3

-x/-1 = -0.5y/-1 - 3/-1

x = 0.5y + 3

or

x = 3 + 0.5y
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X/8 + 12 = 15
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Molodets [167]

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8x^8/3 y^4 - The first option

Step-by-step explanation:

The first thing we need to do is the exponent outside the bracket and leave the 8 till last, because exponents always come before multiplying coefficients. When an term with an exponent is multiplied by another exponent outside a bracket, the exponents of both terms are multiplied by the exponent outside the bracket.

This means that the expression is now:

8(x^2*4/3 y^3*4/3)

First we can so the x term. The x term already has an exponent of 2, so the 2 is multiplied by the 4/3 exponent outside the bracket. 2*4/3 = 8/3, so the x term is now: x^8/3

The same happens to the y term: 3*4/3 simplifies to 4, so the y term is now y^4.

So now our expression is:

8(x^8/3 y^4)

Now the 8 outside the bracket simply multiplies on to the whole term so we finish with:

8x^8/3 y^4 - The first option.

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