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Natalija [7]
3 years ago
15

The sales manager of a company awarded a total of \$3000$3000 in bonuses to the most productive salespeople. The bonuses were aw

arded in amounts of \$250$250 or \$750$750. If at least one \$250$250 bonus and at least one \$750$750 bonus were awarded, what is one possible number of \$250$250 bonuses awarded?
Mathematics
1 answer:
alisha [4.7K]3 years ago
4 0

Answer:

one possible number of bonus is 9.

Step-by-step explanation:

Let, the number of $250 bonus = x and number of $750 bonus = y.

We have that bonuses are given in amounts $250 and $750.

Since, the total bonus is $3000.

So, we get,

250x + 750y = 3000.

As, there is atleast one $250 bonus and atleast one $750 bonus.

Let, the minimum number of bonus of $750 be 1 i.e. y = 1.

Substitute in the equation gives,

250x + 750 × 1 = 3000

i.e. 250x = 3000 - 750

i.e. 250x = 2250

i.e. x = 9

Thus, the maximum number of $250 bonus are 9.

Hence, one possible number of bonus is 9.

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N +8=4<br> Well I’m stupid so someone help
Vladimir [108]

Answer:

n = - 4

Step-by-step explanation:

n + 8 = 4

n = 4 - 8

n = - 4

8 0
3 years ago
Truck A costs $600 more that Truck B. However, it burns 0.06 gallon/mile compared to 0.07 gallon/mile for truck B. Both trucks h
qwelly [4]

Answer:

  1,778

Step-by-step explanation:

Let C and S represent the cost and salvage value of Truck B, respectively. Let X represent the number of miles per year that answers the question.

Truck A's cost for 10 years is ...

  A = C+600 +(0.06)(2.25)(10X) -(S+200)

Truck B's cost for 10 years is ...

  B = C +(0.07)(2.25)(10X) -S

We want to find X such that Truck A's cost is lower, so ...

  C -S +1.35X +400 < C -S +1.575X

  400 < 0.225X

  1777 7/9 < X

1778 miles driven per year (or more) makes Truck A a better option.

5 0
3 years ago
ILL GIVE YOU BRAINLIST !!!
kifflom [539]

3m+8-2m^3

M=-1

3x-1=-3

-2x-1=-2

-3+8+2^3

2x2=4x2=8

-3+8+8

-3+16 or 16-3

13

Hope it helps!

4 0
2 years ago
Read 2 more answers
At a leather shop, 50 leather jackets were sold in February. The shop keeper at the store wants to encourage the sales team to s
Doss [256]
You would have to first multiply 50 by 30% and you should get 15. Then you add 15 jackets to 50 and get 65 jackets in total.
6 0
3 years ago
In a jury trial, suppose the probability the defendant is convicted, given guilt, is 0.95, and the probability the defendant is
Artyom0805 [142]

Answer:

The probability of the defendant is innocent given the defendant is convicted is P=0.006.

Step-by-step explanation:

Being:

G: guilty, I:innocent, C: convicted, A: acquitted.

We need to calculate P(I|C).

Being innocent, given convicted, is equal to the probability of being innocent and convicted divided by the probability of being convicted (innocent or guilty)

P(I|C)=\frac{P(I\&C)}{P(C)}

The probability of being innocent and convicted is

P(I\&C)=P(C|I)*P(I)=0.05*0.1=0.005

The probability of being convicted is equal to the sum of P(I&C) and P(G&C)

P(C)=P(I\&C)+P(I\&C)=P(C|I)*P(I)+P(C|G)*P(G)\\\\P(C)=0.005+0.95*0.90=0.005+0.855=0.86

Then,

P(I|C)=\frac{P(I\&C)}{P(C)}=\frac{0.005}{0.86}= 0.006

6 0
3 years ago
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