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horsena [70]
3 years ago
10

A school administrator will assign each student in a group of n students to one of m classrooms. If 3 < m < 13 < n, is

it possible to assign each of the n students to one of the m classrooms so that each classroom has the same number of students assigned to it?
Mathematics
1 answer:
tatiyna3 years ago
4 0

Answer:

Hence to get same number of students in each classroom,the sufficient condition is that assign 13n students to each classroom.

Step-by-step explanation:

Given:

There are m classrooms and n be the students

3<m<13<n.

To Find:

Whether it is possible to assign each of n students to one of m classrooms with same no.of students.

Solution:

This problem is related to p/q form  has to be integer in order to get same no of students assigned to the classroom.

As similar as ,n/m ratio

So 1st condition is that,

If it is possible to assign the n/m must be integer and n should be multiple of m,

when we assign 3n students to m classrooms ,we cannot say that 3n/m= integer so that  n is greater than 13 i.e n=14 and m=6

hence they are not multiple of each other so they will not make same students in each classrooms.

Otherwise,n=14 and m=7 they will give same number but this condition is not sufficient condition to assign the student.

So 2nd condition is that ,

When we assign 13n students to m classrooms, as 13 is prime number and

3<m<13 which implies the 13n/m to be integer so n and m must be multiple of each other.

Suppose n=20 and m=5 classrooms

then 13*20=260 ,

260/5=52 students in each classroom,

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krok68 [10]

Answer:

The jeweler made 9 necklaces.

The jeweler made 8 bracelets.

Step-by-step explanation:

x = number of bracelets

y = number of necklaces

17 = x + y

238 = 5x + 22y

Make one of the coefficients, x, the same.

17 = x + y

Multiply this equation by 5.

85 = 5x + 5y

Subtract the equations to get rid of x.

(238 = 5x + 22y) - (85 = 5x + 5y)

(5x - 5x) + (22y - 5y) = 238 - 85

22y - 5y = 238 - 85

17y = 153

y = 153/17 = 9

The jeweler made 9 necklaces. Substitute this back into one of the equations to find x.

17 = x + y

17 = x + 9

17 - 9 = x

x = 8

238 = 5x + 22y

238 = 5x + 22(9)

238 = 5x + 198

238 - 198 = 5x

40 = 5x

x = 40/5

x = 8

The jeweler made 8 bracelets.

8 0
3 years ago
Geometry: fill in the blanks (ASAP!! It’s urgent)
stepladder [879]

5. m∠C = 95°

6. m∠C = 70°

7. The other acute angle in the right triangle = 70°

8. m∠C = 70°

9. m∠C = 60° [equilateral triangle]

10. Measure of the exterior angle at ∠C = 110°

11. m∠B = 70°

12. m∠Z = 70°

<h3>What are Triangles?</h3>

A triangle is a 3-sided polygon with three sides and three angles. The sum of all its interior angles is 180 degrees. Some special triangles are:

  • Isosceles triangle: has 2 equal base angles.
  • Equilateral triangle: has three equal angles, each measuring 60 degrees.
  • Right Triangle: Has one of its angles as 90 degrees, while the other two are acute angles.

5. m∠C = 180 - 50 - 35 [triangle sum theorem]

m∠C = 95°

6. m∠C = 180 - 25 - 85 [triangle sum theorem]

m∠C = 70°

7. The other acute angle in the right triangle = 180 - 90 - 25 [triangle sum theorem]

The other acute angle = 70°

8.  m∠C = 180 - 55 - 55 [isosceles triangle]

m∠C = 70°

9. m∠C = 60° [equilateral triangle]

10. Measure of the exterior angle at ∠C = 50 + 60

Measure of the exterior angle at ∠C = 110°

11. m∠B = 115 - 45

m∠B = 70°

12. m∠Z = 180 - 35 - 75

m∠Z = 70°

Learn more about triangles on:

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8 0
2 years ago
Match the equations with their solutions over the interval [0, 2π].
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I solved this using a scientific calculator and in radians mode since the given x's is between 0 to 2π. After substitution, the correct pairs are:

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sec(x)cot(x) + 2 = 0 → 7π/6 and 11π/6

sec(7π/6)cot(7π/6) + 2 = 0

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csc(x)tan(x) – 2 = 0 → π/3 and 5π/3

csc(π/3)tan(π/3) – 2 = 0

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Answer:

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