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horsena [70]
3 years ago
10

A school administrator will assign each student in a group of n students to one of m classrooms. If 3 < m < 13 < n, is

it possible to assign each of the n students to one of the m classrooms so that each classroom has the same number of students assigned to it?
Mathematics
1 answer:
tatiyna3 years ago
4 0

Answer:

Hence to get same number of students in each classroom,the sufficient condition is that assign 13n students to each classroom.

Step-by-step explanation:

Given:

There are m classrooms and n be the students

3<m<13<n.

To Find:

Whether it is possible to assign each of n students to one of m classrooms with same no.of students.

Solution:

This problem is related to p/q form  has to be integer in order to get same no of students assigned to the classroom.

As similar as ,n/m ratio

So 1st condition is that,

If it is possible to assign the n/m must be integer and n should be multiple of m,

when we assign 3n students to m classrooms ,we cannot say that 3n/m= integer so that  n is greater than 13 i.e n=14 and m=6

hence they are not multiple of each other so they will not make same students in each classrooms.

Otherwise,n=14 and m=7 they will give same number but this condition is not sufficient condition to assign the student.

So 2nd condition is that ,

When we assign 13n students to m classrooms, as 13 is prime number and

3<m<13 which implies the 13n/m to be integer so n and m must be multiple of each other.

Suppose n=20 and m=5 classrooms

then 13*20=260 ,

260/5=52 students in each classroom,

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7 0
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There are 24 boys and 16 grils on a playground. What is the ratio of boys tototal number of children on the playground
tatuchka [14]

Answer:

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Step-by-step explanation:

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Write the equation of the line in slope intercept from given the slope of the line is m=3 and the line passes through the point
inna [77]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
Find the length of MN.<br> A) 7 <br> B) 25 <br> C) 32 <br> D) 39
MrRissso [65]

Step-by-step explanation:

Answer C)

Explanation:

MN + NP = MP

MP = 39

Therefore, 4(x + 5) + 2x + 1= MP

So, 4(x + 5) + 2x + 1= 39

(4x + 20) + 2x +1 = 39

So, (4x + 2x) + (20 + 1) = 39

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Addition changes to Subtraction

So, 6x = 39 - 21

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Multiplication changes to Division

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Therefore MN = 4(x + 5)

So, 4(3 + 5) = 4(8)

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Therefore, MN = 32

Hope this helps!

3 0
3 years ago
Is this correct? If not, which one is it? Thanks in advance!
Lisa [10]

Answer:

its the the second one not the first one



7 0
3 years ago
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