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Anarel [89]
3 years ago
6

Roll two 6-sided dice and examine their sum.

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
5 0
<span>a) How long will it take to roll "snake-eyes" (a pair of ones)?
P(a pair of ones) = 1/36
Therefore, it takes 36 rolls to roll "snake-eyes".

b) What is the probability of rolling a sum of 7 on the first roll?
P(a sum of 7) = 6/36 = 1/6
P(a sum of 7 on the first roll) = 1/6

c) What is the probability of rolling a sum of 7 on the fourth roll?
P(a sum of 7 on the fourth roll) = </span><span><span>(5/6)^3 * 1/6 = 125/1296</span>

d) What is the probability of rolling a sum of 7 by the fourth roll?
P(a sum of 7 by the fourth roll) = 1/6 + (5/6) * 1/6 + (5/6)^2 * 1/6 + (5/6)^3 * 1/6 = 1/6 + 5/36 + 25/216 + 125/1296 = 671/1296

e) What is the probability of it takin</span>g more than 10 rolls to roll the sum of 7?
P(more than 10 rolls to roll the sum of 7) = 1 - P(no sum of 7 in the first 10 rolls) = 1 - (5/6)^10 = 1 - 0.1615 = 0.8385

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PLEASE HELP!!
aliya0001 [1]

Ik this is late, but people who are looking for the answer can see this.

Answer:

an =1/3*6^n-1

Step-by-step explanation:

You should plug in 2 for n in each equation, which, the correct one should give you 2. Then, to make sure, you plug in 3 in the equations that gave you 2.

Example:

an = 1/3 * 6 ^n-1

Plug in 2.

an = 1/3 * 6 ^2-1

an = 1/3 * 6 ^1

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Step 2.

an = 1/3 * 6 ^3-1

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