Answer:
>60
Step-by-step explanation:
The difference in miles is 0.25 per mile. Because there is 15$ difference in initial payment then after 60 miles (60x0.25=$15) A will be better option. At $60 A and B are same and lower than B is better
Step-by-step explanation:
Inverse of
y
=
x
+
3
x
−
2
is
y
=
2
x
+
3
x
−
1
Explanation:
As
y
=
x
+
3
x
−
2
x
y
−
2
y
=
x
+
3
or
x
y
−
x
=
2
y
+
3
or
x
(
y
−
1
)
=
2
y
+
3
or
x
=
2
y
+
3
y
−
1
Hence inverse of
y
=
x
+
3
x
−
2
is
y
=
2
x
+
3
x
−
1
Observe that each of the function is a reflection of the other in the line
x
=
y
.
graph{(y-(x+3)/(x-2))(y-(2x+3)/(x-1))(x-y)=0 [-10, 10, -5, 5]}
5
1
-3
These are your answers
Answer:
Dimensions will be
Length = 7.23 cm
Width = 7.23 cm
Height = 9.64 cm
Step-by-step explanation:
A closed box has length = l cm
width of the box = w cm
height of the box = h cm
Volume of the rectangular box = lwh
504 = lwh
![h=\frac{504}{lw}](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B504%7D%7Blw%7D)
Sides which involve length and width and height, cost = 3 cents per cm²
Top and bottom of the box costs = 4 cents per cm²
Cost of the sides
= 3[2(l + w)h] = 6(l + w)h
= 3[2(l + w)h]
![C_{s}=6(l+w)(\frac{504}{lw} )](https://tex.z-dn.net/?f=C_%7Bs%7D%3D6%28l%2Bw%29%28%5Cfrac%7B504%7D%7Blw%7D%20%29)
Cost of the top and the bottom
= 4(2lw) = 8lw
Total cost of the box C =
+ 8lw
=
+ 8lw
To minimize the cost of the sides
![\frac{dC}{dl}=3024(-l^{-2}+0)+8w=0](https://tex.z-dn.net/?f=%5Cfrac%7BdC%7D%7Bdl%7D%3D3024%28-l%5E%7B-2%7D%2B0%29%2B8w%3D0)
![\frac{3024}{l^{2}}=8w](https://tex.z-dn.net/?f=%5Cfrac%7B3024%7D%7Bl%5E%7B2%7D%7D%3D8w)
---------(1)
![\frac{dC}{dw}=3024(-w^{-2})+8l=0](https://tex.z-dn.net/?f=%5Cfrac%7BdC%7D%7Bdw%7D%3D3024%28-w%5E%7B-2%7D%29%2B8l%3D0)
![\frac{3024}{w^{2}}=8l](https://tex.z-dn.net/?f=%5Cfrac%7B3024%7D%7Bw%5E%7B2%7D%7D%3D8l)
-------(2)
Now place the value of w from equation (1) to equation (2)
![(\frac{378}{l^{2}})^{2}=\frac{378}{l}](https://tex.z-dn.net/?f=%28%5Cfrac%7B378%7D%7Bl%5E%7B2%7D%7D%29%5E%7B2%7D%3D%5Cfrac%7B378%7D%7Bl%7D)
![\frac{(378)^{2} }{l^{4}}=\frac{378}{l}](https://tex.z-dn.net/?f=%5Cfrac%7B%28378%29%5E%7B2%7D%20%7D%7Bl%5E%7B4%7D%7D%3D%5Cfrac%7B378%7D%7Bl%7D)
l³ = 378
l = ∛378 = 7.23 cm
From equation (2)
![w^{2}=\frac{378}{7.23}](https://tex.z-dn.net/?f=w%5E%7B2%7D%3D%5Cfrac%7B378%7D%7B7.23%7D)
![w^{2}=52.28](https://tex.z-dn.net/?f=w%5E%7B2%7D%3D52.28)
w = 7.23 cm
As lwh = 504 cm³
(7.23)²h = 504
![h=\frac{504}{(7.23)^{2}}](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B504%7D%7B%287.23%29%5E%7B2%7D%7D)
h = 9.64 cm
there is not enough information