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Lady_Fox [76]
3 years ago
11

urgent!! - What is the perimeter of a parallelogram, if it's area is 36 cm2 and the distances between the point of intersection

of the diagonals and the sides are 2 cm and 3 cm?
Mathematics
1 answer:
Gennadij [26K]3 years ago
6 0

Answer:

  30 cm

Step-by-step explanation:

The distance from the intersection of the diagonals (center of the parallelogram) to one side is half the height when that side is considered the base.

So, if the height is 2×(2 cm) = 4 cm, and the area is 36 cm², the base for that height must be ...

  (36 cm²)/(4 cm) = 9 cm.

Similarly, if the height is 2×(3 cm) = 6 cm, the base for that height is ...

  (36 cm²)/(6 cm) = 6 cm.

These "bases" are the side lengths of the parallelogram, so its perimeter is ...

  P = 2(s1 +s2) = 2(9 cm +6 cm) = 30 cm

The perimeter of the parallelogram is 30 cm.

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From the question we are told that:

Distance of hole from tee d_h=340yards

Distance to the right d_r=230yards

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Given that the three points form a triangle x,y,z respectively

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Using Cosine Rule

yz^2=xy^2+xz^2-2(xy)(xz)cos\phi

Therefore

cos\phi=\frac{yz^2}{xy^2+xz^2-2(xy)(xz)}

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In conclusion the angle the golfer went off line from the tee when they

drove the ball is mathematically deducted and give as

\phi=28.2 \textdegree

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