2+6g=11-3g
-2+3g -2+3g
9g=9
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9. 9
G=1
![\sqrt{20} = \sqrt{4} \sqrt{5} = 2 \sqrt{5}](https://tex.z-dn.net/?f=%20%5Csqrt%7B20%7D%20%3D%20%20%5Csqrt%7B4%7D%20%20%5Csqrt%7B5%7D%20%20%3D%202%20%5Csqrt%7B5%7D%20)
![\sqrt{24} = \sqrt{4} \sqrt{6} = 2 \sqrt{6}](https://tex.z-dn.net/?f=%20%5Csqrt%7B24%7D%20%3D%20%20%5Csqrt%7B4%7D%20%5Csqrt%7B6%7D%20%3D%202%20%5Csqrt%7B6%7D%20)
![\sqrt{54} = \sqrt{9} \sqrt{6} = 3 \sqrt{6}](https://tex.z-dn.net/?f=%20%5Csqrt%7B54%7D%20%3D%20%20%5Csqrt%7B9%7D%20%5Csqrt%7B6%7D%20%3D%203%20%5Csqrt%7B6%7D%20%20%20%20)
Because you can only add and subtract radicals with the same radicand,
you get 2
![\sqrt{5} - \sqrt{6}](https://tex.z-dn.net/?f=%20%5Csqrt%7B5%7D%20-%20%20%5Csqrt%7B6%7D%20)
that is the simplified answer but if you want it in decimals, 2.022 is what you get.
First you do 4500 × 0.04
Then take that number and add it to 4500
The answer is 81 < < 105
Explanation: Since the car gets 27 mpg in the city and gets 35 mpg on the highway, you can set it up in the inequality 27 < < 35 and this represents the range a car can drive for 1 gallon, so to find the range for 3 gallons, you multiply this inequality by 3.
27(3)<<35(3)
27(3)=81
35(3)=105
Then you can insert the numbers into the inequality to get 81<<105.
Answer:
Step-by-step explanation:
180 - 152 = 28
2x + 28 = 180
2x = 152
x = 76