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Anna11 [10]
3 years ago
15

An insurance company is considering implementing a plan based on mileage. The current plan, Plan A, charges a flat rate of $269.

60 per month. Plan B charges a flat rate of $180.80 per month plus an additional $0.08 per mile driven the previous month. Using the inequality below, find the number of miles, x, where the cost of Plan B is less than the cost of Plan A. $180.80 + $0.08x < $269.60
Mathematics
1 answer:
timama [110]3 years ago
6 0

Answer:

88.72

Step-by-step explanation:

180.08 .0.08=180.88 subtract from 269.60 =88.72

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2x+8&lt;5x-4 solve the inequality
nataly862011 [7]

Answer:

x>4

Step-by-step explanation:

2x+8<5x-4

subtract 8 from both sides

2x<5x-12

subtract 5x from both sides

-3x<-12

divide both sides by -3 to get x by itself

(REMEMBER THAT WHEN YOU DIVIDE BY NEGATIVES IN INEQUALITIES, THAT YOU HAVE TO FLIP THE INEQUALITY SIGN)

x>4

5 0
3 years ago
The length of a rectangle is (x - 9) feet. Its width is x feet. Write an expression you could use to find the perimeter
steposvetlana [31]

Answer:

The expression for the perimeter of the rectangle is: P = 4x - 18

Step-by-step explanation:

Perimeter of a rectangle:

A rectangle has length l and width w. It's perimeter is given by:

P = 2(l + w)

In this question:

l = x - 9, w = x

So

P = 2(x - 9 + x) = 2(2x - 9) = 4x - 18

The expression for the perimeter of the rectangle is: P = 4x - 18

6 0
3 years ago
Elasticity of Demand The demand function for a certain brand of backpacks is
Trava [24]

Answer:

See explanation

Step-by-step explanation:

Solution:-

- The demand function of a certain brand is given as price P a function of x quantity of goods ( in hundred ) demanded per month. The relation is:

                           P ( x ) = 50 Ln ( 50 / x ).

- The point price elasticity ( E ) of demand is given by:

                           E = \frac{P}{x}*\frac{dP}{dx}  

- Where, dP / dx : is the rate of change of price ( P ) with each hundred unit of good ( x ) is demanded.

- To determine the " dP / dx " by taking the first derivative of the given relation:

                          P ( x ) = 50 Ln ( 50 / x ).

                          d P ( x ) / dx = [ 50*x / 50 ] * [ -1*50 / x^2 ]

                                              = - 50 / x

- Hence the point price elasticity of demand is given by:

                          E = - ( P / x ) * ( 50 / x )

                          E = -50*P / x^2    

- For an inelastic demand, ! E ! is < 1:

                          ! -50*P / x^2 ! < 1

                          50*P / x^2 < 1

                          P < x^2 / 50

- For an unitary demand, ! E ! is =  1:

                          ! -50*P / x^2 !  = 1

                          50*P / x^2 = 1

                          P = x^2 / 50

- For an inelastic demand, ! E ! is > 1:

                          ! -50*P / x^2 ! > 1

                          50*P / x^2 > 1

                          P > x^2 / 50

2)

If the unit price is increased slightly from $50, will the revenue increase or decrease?

- We see from the calculated demand sensitivity d P / dt:

                          d P ( x ) / dx = - 50 / x

- We see that as P increases the from P = $50, the quantity of goods demanded would be:

                          50 = 50 ln(50/x)

                           1 = Ln ( 50 / x )

                           50/x = e

                           x = 50 / e

Then,

                          d P ( x ) / dx = - 50 / ( 50 / e )

                          d P ( x ) / dx = - e

- We see that if price slightly increases from $ 50 then the quantity demanded would decrease by e (hundreds ) goods.

- The decrease in the quantity demanded is higher than the increase in price. The revenue is given by the product of price P ( x ) and x:

                Revenue R ( x ) = P ( x ) * x

                                = 50*x*ln(50/x)

Then the product of price and quantity goods also decreases; hence, revenue decreases.

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3 years ago
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The mid point would be (1,25.5)
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How many hours is 6:30am to 1:50pm
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