Exponential decay is given by the equation
F = P(1 - r)^t
0.5 = 1(1 - 0.092)^t
0.5 = (0.908)^t
log 0.5 = log (0.908)^t
log 0.5 = t * log 0.908
t = (log 0.5)/(log 0.908)
t = 7.18
Answer: 7.2 years
I'm pretty sure that you need to multiply pie times the radius of the circle
<h2>Answer = </h2><h2>

</h2>
Step-by-step explanation:
Greetings !
simplify for variable y first
apply exponent rule

Add/subtract the numbers -8+3=5

Apply exponent rule

Thus,

secondly, simplify for the variable x
Apply exponent rule as we made on y


multiply bot the values we get
Hope it helps!
Answer:
<h2><em><u>3</u></em></h2>
Step-by-step explanation:
<h3>
<u>Given</u><u> </u><u>question</u><u>:</u></h3>
<em>To</em><em> </em><em>simplify</em><em> </em><em>-</em><em> </em>

<h3>
<u>Solution</u><u>:</u></h3>
<em>According</em><em> </em><em>to</em><em> </em><em>PEMDAS</em><em> </em><em>rule</em><em>,</em>
- <em>[</em><em>First</em><em> </em><em>parenthesis</em><em>]</em>


- <em>[</em><em>Then</em><em> </em><em>exponents</em><em>]</em>

- <em>[</em><em>Then</em><em> </em><em>multiplication</em><em>]</em>
= 14 + 16 ÷ 8 - 21 ÷ 7 - 10
- <em>[</em><em>Then</em><em> </em><em>division</em><em>]</em>
= 14 + 2 - 3 - 10
- <em>[</em><em>Then</em><em> </em><em>addition</em><em>]</em>
= 16 - 13
- <em>[</em><em>Then</em><em> </em><em>subtraction</em><em>]</em>
= <em><u>3</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>