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tankabanditka [31]
3 years ago
9

10x(15w-11)+12 what is it help me

Mathematics
1 answer:
RUDIKE [14]3 years ago
5 0
If im not wrong the answer is 150w - 98.
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Find the following sums. Please help.
34kurt

Answer:

5m-n-4p

4a^2+6x-3

Step-by-step explanation:

3m-4n +7p

-5m +9n -6p

+7m -6n -5p

----------------------

Combine like terms

3m-4n +7p

-5m +9n -6p

+7m -6n -5p

----------------------

(3-5+7)m  +(-4+9-6)n  +(7-6-5)p

5m-n-4p

a^2  -3x +1

a^2   +9x -6

2a^2 +0x +2

----------------------

Combine like terms

a^2  -3x +1

a^2   +9x -6

2a^2 +0x +2

----------------------

(1+1+2)a^2 +(-3+9+0)x +(1-6+2)

4a^2+6x-3

6 0
2 years ago
Math Story problem. I need help
Olin [163]

Answer:

i believe it would be 12

hope this helps !!

Step-by-step explanation:

96 divided by 8 would equal 12 so therefore the answer is 12

6 0
2 years ago
Please help ! i'll give brainliest to the first person who gets it right ! :,>
telo118 [61]

Answer:

±16

Step-by-step explanation:

the square root of 256 is positive or negative 16! (if it only lets you put one answer, put positive 16).

4 0
2 years ago
Read 2 more answers
A club consisting of 6 juniors and 8 seniors is to be formed from a group of 13 juniors and 16 seniors. How many different clubs
Vilka [71]

Answer: 22,084,920 different clubs

Step-by-step explanation:

The club must have 6 juniors and 8 seniors

We have a total of 13 juniors and 16 seniors.

Now, we know that the possible combinations of N objects into a group of K is equal to:

C = \frac{N!}{(N-K)!*K!}

For the juniors we have N = 13 and K = 6

Cj = \frac{13!}{7!*6!} = \frac{13*12*11*10*9*8}{6*5*4*3*2*1} = 1716

For the seniors we have N = 16 and K = 8

Cs = \frac{16!}{8!8!}  = \frac{16*15*14*13*12*11*10*9}{8*7*6*5*4*3*2*1} = 12870

Now, as the group consist on both combinations togheter, the number of different clubs that can be formed are:

C = Cj*Cs = 1,716*12,870 = 22,084,920

5 0
2 years ago
Help me pls pls pls i really need help
Monica [59]
The answer is A..... 2 2/3
8 0
2 years ago
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