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grandymaker [24]
3 years ago
8

(c) How many components would be needed in the structure so that the probability the system will succeed is greater than​ 0.9999

?
Mathematics
1 answer:
Murljashka [212]3 years ago
5 0
Prob. of a system can be a failure is less than (1-0.9999) = 0.0001 

<span>now probability that the system will be failure when it has x components is </span>
<span>(0.2)^x </span>

<span>so, (0.2)^x < 0.0001 </span>
<span>or, x*log0.2 < log0.0001 </span>
<span>or, x > log0.0001/log0.2 [the sign changes coz log 0.2 is negative] </span>
<span>or, x > 5.7227 </span>

<span>so, the no. of components (x) has to be 6</span>
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This sequence comes from a pattern of dots that form a triangle:

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A Rule

We can make a "Rule" so we can calculate any triangular number.

First, rearrange the dots (and give each pattern a number n), like this:

Then double the number of dots, and form them into a rectangle:

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And we get (remembering we doubled the dots):

<span>2xn = n(n+1)</span><span>xn = n(n+1)/2</span>

<span>Rule: xn = n(n+1)/2</span>

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Wasn't it much easier to use the formula than to add up all those dots?

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