Dave Fletcher was able to determine the activity times for constructing his laser scanning machine. Fletcher would like to deter
mine ES, EF, LS, LF, and slack for each activity. The total project completion time and the critical path should also be determined. Here are the activity times: Activity Time (weeks) Immediate Predecessor(s) Activity Time (weeks) Immediate Predecessor(s) A 5 minus E 4 B B 6 minus F 5 B C 4 A G 11 C, E D 2 A H 6 D , F
1 answer:
Answer:
- Project completion time: 21 weeks
- Critical Path: B - E - G
- ES, EF, LS, LF are shown below
Explanation:
The earliest start is the latest of the earliest finish times of the predecessors. The earliest finish is the sum of earliest start and duration.
The latest finish is the earliest of the latest start times of the successors. The latest start is the difference of latest finish and duration.
The slack is the difference between earliest start (or finish) and latest start (or finish).
Project duration is the earliest start of the "Project Done" task. For purposes of computing slack, this (project duration) is taken to be the latest finish of the immediate predecessors.
The critical path is the sequence of tasks with 0 slack.
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