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Fofino [41]
4 years ago
6

How do you simplify radicals?

Mathematics
1 answer:
Vinvika [58]4 years ago
3 0
1) First try to find a perfect square number that divides evenly into the number under the square root. Perfect square numbers include 4, 9, 16, 25, 36, 49, etc. because they are squares of the numbers 2, 3, 4, 5, 6, 7, etc., respectively.

2) Separate the root expression into the two numbers you found as factors, with each number now under its own square root symbol. For example, sqrt(12) = sqrt(4) times sqrt(3).

3) Keep simplifying. The square root of a perfect square becomes just a number, without the radical square root symbol. sqrt(4)*sqrt(3) becomes 2*sqrt(3).

4) Check to see if anymore simplifying can be done, either by combining constants or finding another perfect square number that divides evenly into your factors. If no more simplifying can be done, you have your final "simplified radical form" (SRF) answer, 2*sqrt(3).

If there is a square root anywhere in the DENOMINATOR, you must "rationalize" the denominator, in other words, somehow get rid of the root in the bottom, in order for the expression to be considered simplest. For example, if you have 4/sqrt(2) you must use the trick of simplifying by multiplying the expression by sqrt(2)/sqrt(2). This will clear the square root in the bottom. If you multiply straight across, you would get 4*sqrt(2)/2, which simplifies again to 2*sqrt(2).

<span>If you have a more complicated fraction with a square root in the denominator, like (4+sqrt(3))/(5-sqrt(3)), you will need to use the "conjugate" to simplify. This means multiplying top and bottom by the expression in the denominator, but with the middle sign flipped. Here you would multiply by (5+sqrt(3))/(5+sqrt(3)), multiply straight across on top and bottom using FOIL-ing and distribution. Some terms will cancel in the bottom, leaving you with a simpler denominator that has no square roots.</span>
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How do you call the number pair that is used to describe a point on a plane​
Degger [83]

Answer:

Maybe ordered pair

Step-by-step explanation:

I'm guessing you meant like what is it called

5 0
3 years ago
Order these numbers from least to greatest<br><br> 151/20, 7 6/11, 7.32, 7.546
Anton [14]

Answer:

76/11 ; 7.32 ; 7.546 ; 151/20

Step-by-step explanation:

Given data:

The numbers are listed as below

151/20 ; 76/11 ; 7.32 ;7.546

The numbers are written in the same format that is in decimal form

7.55 ; 6.90901 ; 7.32 ; 7.546

Arranging the numbers starting with the least number

6.90901 ; 7.32 ; 7.546 ; 7.55

76/11 ; 7.32 ; 7.546 ; 151/20

Please note the value of 151/20 is exactly 7.550 which makes it larger than 7.546.

4 0
3 years ago
Please help me with this question! Thank you :)
madreJ [45]

Answer:

y=x-3

Step-by-step explanation:

Graph y=x-5 and the point (1,-2). You want your slope to be the same for the lines to be parallel. The slope in the given equation is 1/1. Type into a graphing calculator y=x- and pick a number greater than negative five since the point (1,-2) is above the given line. Guess and checking reveals -3 to be the correct answer. Therefore, your answer is y=x-3.

5 0
3 years ago
I need help with this!! Pls help.
ExtremeBDS [4]

Answer:

-  \frac{3}{2} and \:  \frac{1}{3}

8 0
3 years ago
Please help! 50 points and i'll give brainliest!
lorasvet [3.4K]

Answer:

36\sqrt{3} -12\pi

Step-by-step explanation:

The area of the shaded portion, we have to calculate.

Now, join C and O to form two right triangles Δ AOC and Δ BOC.

Now, from Δ AOC,  

\tan 60 = \frac{AC}{AO} = \frac{x}{6}

⇒ x = 6√3  

So, area of Δ AOC = \frac{1}{2} \times 6 \times 6\sqrt{3}  = 18\sqrt{3}

Due to symmetry area of Δ BOC will also be 18√3.

Now, area of quadrilateral OACB is 2 × 18√3 = 36√3

Now, area covered by the arc AB about center O will be \frac{120}{360} \times \pi r^{2} = 12\pi

Therefore, the area of the shaded portion is 36\sqrt{3} -12\pi (Answer)

4 0
4 years ago
Read 2 more answers
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