PLEASE HELP WITH #17 AND #6

Mathematics

1 answer:

IgorC [24]3 years ago

7 0

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Negative 3/2 times negative 5 1/4

Travka [436]

You mean -3/2 * -51/4???

use the calculator to multiply them and you will get 19.125

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3 years ago

6 1/2 + 3.5 x 2 - 7 divided by 3<br><br> Which operation should be performed first?

S_A_V [24]

Answer:

I think PEMDAS would be helpful for this.

Step-by-step explanation:

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3 years ago

Que es la media ponderada?

Roman55 [17]

Answer:

Step-by-step explanation:

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3 years ago

Cot^2x/cscx-1=1+sinx/sinx

KATRIN_1 [288]

$\bf \textit{difference of squares}
\\\\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
-------------------------------\\\\
\cfrac{cot^2(x)}{csc(x)-1}=\cfrac{1+sin(x)}{sin(x)}\impliedby \textit{let's do the left-hand-side}$

$\bf \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1}{sin(x)}-1}\implies \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1-sin(x)}{sin(x)}}\implies \cfrac{cos^2(x)}{sin^2(x)}\cdot \cfrac{sin(x)}{1-sin(x)}
\\\\\\
\cfrac{cos^2(x)}{sin(x)}\cdot \cfrac{1}{1-sin(x)}\implies \cfrac{cos^2(x)}{sin(x)[1-sin(x)]}$

$\bf \cfrac{1-sin^2(x)}{sin(x)[1-sin(x)]}\implies \cfrac{1^2-sin^2(x)}{sin(x)[1-sin(x)]}
\\\\\\
\cfrac{\underline{[1-sin(x)]}~[1+sin(x)]}{sin(x)\underline{[1-sin(x)]}}\implies \cfrac{1+sin(x)}{sin(x)}$

5 0

3 years ago

How do you do this??

Alex777 [14]

The formula for the circumference of a circle = 2 x radius x pi

The radius is given as 21 cm and pi = 3.142

Circumference = 2 x 21 x 3.142 = 131.964 cm

6 0

2 years ago

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