Let the smaller number be x.
Given, the larger number is 7 times the smaller number.
So, the larger number = 7x.
Given, 3 times the larger number is 7 more than 4 times the smaller number.
So we can write the equation as,



Now we have to move 4x to the left side by subtracting 4x from both sides.



To get x, we will divide both sides by 17. We will get,


So the smaller number = 
The larger number =
= 
So we have got the required numbers.
Smaller number =
and larger number =
.
Answer: b) two sides and the included angle are congruent
<u>Step-by-step explanation:</u>
RS = QS SIDES are congruent
∠PSR ≡ ∠PSQ ANGLES are congruent
PS = PS SIDES are congruent
ΔPSR ≡ ΔPSQ by the Side-Angle-Side (SAS) Congruency Theorem
Since we know the triangles are congruent, we can state that their parts are congruent:
Congruent-Parts of-Congruent-Triangles are-Congruent (CPCTC)
If you add the standard deviation to the average, it is 14.84. Because Marcus's score was lower than that, he will not receive a certificate.
I think this should be right for the reason and the calculation.
M² - 12m + 20
m² ⇒ m * m
20 ⇒ - 10 * -2
(m - 10)(m - 2)
m(m - 2) - 10(m-2)
m² - 2m - 10m + 20
m² - 12m + 20
m - 10 = 0
m = 10
m - 2 = 0
m = 2
Answer:
2 hours, 150 miles
Step-by-step explanation:
The relation between time, speed, and distance can be used to solve this problem. It can work well to consider just the distance between the drivers, and the speed at which that is changing.
<h3>Separation distance</h3>
Jason got a head start of 20 miles, so that is the initial separation between the two drivers.
<h3>Closure speed</h3>
Jason is driving 10 mph faster than Britton, so is closing the initial separation gap at that rate.
<h3>Closure time</h3>
The relevant relation is ...
time = distance/speed
Then the time it takes to reduce the separation distance to zero is ...
closure time = separation distance / closure speed = 20 mi / (10 mi/h)
closure time = 2 h
Britton will catch up to Jason after 2 hours. In that time, Britton will have driven (2 h)(75 mi/h) = 150 miles.
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<em>Additional comment</em>
The attached graph shows the distance driven as a function of time from when Britton started. The distances will be equal after 2 hours, meaning the drivers are in the same place, 150 miles from their starting spot.