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Brums [2.3K]
3 years ago
8

1. Suppose a and b are real numbers where a > 0 and b < 0.

Mathematics
1 answer:
Nat2105 [25]3 years ago
3 0

a) –a + b is negative

b) a – b is positive

c) b-a is negative

Step-by-step explanation:

1. Suppose a and b are real numbers where a > 0 and b < 0.

a. Is –a + b positive or negative. Explain how you know.

We know a > 0 and b < 0. so, let a =6 and b = -5

Putting values:

–a + b

= -(6)+(-5) = -6-5 = -11

So, –a + b is negative

b. Is a – b positive or negative? Explain how you know.

We know a > 0 and b < 0. so, let a =6 and b = -5

Putting values:

a - b

=6-(-5) = 6+5 = 11

So, a – b is positive

c. Is b – a positive or negative. Explain how you know

We know a > 0 and b < 0. so, let a =6 and b = -5

Putting values:

b-a

=(-5)-(6)

= -5-6

= -11

So, b-a is negative

Keywords: Solving Integers:

Learn more about solving integers at:

  • brainly.com/question/5496711
  • brainly.com/question/11549940
  • brainly.com/question/11334714

#learnwithBrainly

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Part A: y=-\frac{5}{4} x+\frac{35}{2} is the equation of the line.

Part B: Anika worked 17.5 hours on day 0.

Part C: The setup time decreases with 1 hour and 15 min per day.

Explanation:

Part A: Let us find the equation of the line using the points (2,15) and (6,10)

The equation of the line is given by,

y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \cdot\left(x-x_{1}\right)

Substituting, we get,

y-15=\frac{10-15}{6-2} (x-2)

Simplifying, we have,

y-15=-\frac{5}{4} (x-2)

y-15=-\frac{5}{4} x+\frac{5}{2}

Subtracting both sides by 15, we get,

y=-\frac{5}{4} x+\frac{35}{2}

Hence, the equation of the line is y=-\frac{5}{4} x+\frac{35}{2}

Part B: To determine the number of hours Anika worked on day 0, let us substitute x = 0 in the equation of the line.

Thus, we get,

y=\frac{35}{2}\\y=17.5

Hence, Anika worked 17.5 hours on day 0.

Part C: The setup time decrease per day can be determined using the slope.

The formula for slope is given by

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Substituting , we have,

m=\frac{10-15}{6-2}=-\frac{5}{4}

Converting the fraction into hours and minutes, we get,

-\frac{5}{4}\times60=-75 min

Since, 1 hour = 60 min

Subtracting 60 and 75 = 15 min

Thus, the setup time decreases with 1 hour and 15 min per day.

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The given information are the coordinates of points H, Z and B. So, the first step to do is to plot these points on a Cartesian plane as shown in the attached picture. We can deduce visually that horse Z is closer to the barns than horse H. But, to further justify the answer, we have to provide the magnitude of the distance of horses H and Z to barn B. In this approach, we use the distance formula:

d = √(x₂ - x₁)² + (y₂ - y₁)²

Use the coordinates of the two points to know their linear distances. These are represented by the red and green lines for each of the horses.

Distance between H and B = √(⁻3 - 1)² + (⁻9-10)²
Distance between H and B = √(⁻3 - 1)² + (⁻9-10)²
Distance between H and B  = 19.4165

Since the scale is 1 unit = 100 meters, the actual distance between horse H and barn B is 19.416*100 = 1,941.65 meters


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Distance between Z and B = √(⁻3 - 10)² + (⁻9-1)²
Distance between Z and B  = 16.4012

Since the scale is 1 unit = 100 meters, the actual distance between horse Z and barn B is 16.4012*100 = 1,640.12 meters

Comparing the distances: 1,941.65 meters > 1,640.12 meters. Therefore, it justifies that horse Z is nearer to the barn.

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Step-by-step explanation:

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