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ozzi
3 years ago
14

Two Parallel lines are intersected by a transversal /1 and /2 are alternate exterior angles. The measure of /1 is (5x - 16) the

measure of /2 is (4x-2) what is the measure of each angle?
A.m/1=m/2=46
B.m/1=94 and m/2=86
C.m/1=m/2=54
D.m/1=m/2=70
Mathematics
1 answer:
Alecsey [184]3 years ago
6 0

Answer:

C. m/1=m/2=54

Step-by-step explanation:

these two angles are equal hence:

5x-16=4x-2=-16+2 =-14

4x-5x=-x

-x=-14=x=14

then you substitute the value of 'x' with 14

therefore:(5×14-16)=54

(4×14-2)=54

m/1=m/2=54

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The bike store marks up the wholesale cost of all of the bikes they sell by 30%.
aev [14]

Answer:

A ) The money which Andre pay for the bike is $ 67.30

B ) The money which Andre pay for the bike is $ 76.92

Step-by-step explanation:

Given as :

The wholesale cost or market price of the bike = m.p = $ 96.15

A ) The discount percentage = 30 %

Let The selling price of the bike after discount = s.p

Now ,

Discount % = \dfrac{m.p - s. p }{m . p}

or, 30 % = 1 - \dfrac{s. p }{m . p}

or, \dfrac{30 }{100} = 1 - \dfrac{s. p }{96.15}

Or, \dfrac{s. p }{96.15} = 1 -  \dfrac{30 }{100}

or,  \dfrac{s. p }{96.15} =  \dfrac{100 - 30 }{100}

Or,  \dfrac{s. p }{96.15} =  \dfrac{70}{100}

Or, s. p = \dfrac{70}{100} × 96.15

∴  s.p = $ 67.305

So, He will pay $ 67.30

Hence The money which Andre pay for the bike is $ 67.30  . Answer

B ) If the bike is discounted by 20 % , let The selling price = s.p'

So,

Discount % = \dfrac{m.p - s. p }{m . p}

or, 20 % = 1 - \dfrac{s. p' }{m . p}

or, \dfrac{20 }{100} = 1 - \dfrac{s. p' }{96.15}

Or, \dfrac{s. p' }{96.15} = 1 -  \dfrac{20 }{100}

or,  \dfrac{s. p' }{96.15} =  \dfrac{100 - 20 }{100}

Or,  \dfrac{s. p' }{96.15} =  \dfrac{80}{100}

Or, s. p' = \dfrac{80}{100} × 96.15

∴  s.p' = $ 76.92

So, He will pay $ 76.92

Hence The money which Andre pay for the bike is $ 76.92  . Answer

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7. This year, the water in a reservoir dropped by 60%. For the original water level to be restored next year, by what percent mu
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Answer:

Given: Water in a reservoir dropped by 60%

Step-by-step explanation:

let the total water level of reservoir be 100.

then, in first year

the water reservoir dropped = 60% of 100

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therefore, total water level needed to be restored till next year= 100

remaining water level to restore till next year= 100-60

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