D Would be the correct answer.
Where R is the median between Q and L:
From my understanding of a triangle's centroid, it divides an angle bisector into parts of 2/3 and 1/3. In the given problem, these divisions are NS and SR. Therefore, twice SR would be equal to NS. From here, we can get the value of X, to solve for SR.
NS = 2SR
(x + 10) = 2(x + 3)
x + 10 = 2x + 6
x = 4
Therefore, SR = (x + 3) = 7
AND means multiply, so if probability is dependent on two things happening, then we will multiply the individual probabilities together.
1. P(A and 1) = 1/4 x 1/6 = 1/24
2. P(C and 2) = 1/4 x 2/6 = 2/24 = 1/12
3. P(B and 3) = 2/4 x 1/6 = 2/24 = 1/12
4. P(A and 4) = 1/4 x 2/6 = 2/24 = 1/12
5. P(C and 3) = 1/4 x 1/6 = 1/24
6. P(B and 2) = 2/4 x 2/6 = 4/24 = 1/6
7. P(a consonant and an odd #) = 3/4 x 2/6 = 6/24 = 1/4
8. P(a consonant and a prime #) = 3/4 x 3/6 = 9/24 = 3/8
9. P(a vowel and a 5) = 1/4 x 0/6 = 0
10. P(a vowel and a number less than 3) = 1/4 x 3/6 = 3/24 = 1/8
11. P(B and 1) = 2/4 x 1/6 = 2/24 = 1/12
Experimental probability is based on something that has already happened, or data that has already been collected.
12. P(1) = 3/30 = 1/10
13. P(2) = 8/30 = 4/15
14. P(3) = 7/30
15. P(4) = 5/30 = 1/6
16. P(5) = 3/30 = 1/10
17. P(6) = 4/30 = 2/15
Hope this helps!
Total no. of outcomes when two dice are rolled = 36
No. of outcome when 6 will be on both dice = 1
Probability of rolling two 6's = 1/36
Hope this helps!
