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IgorLugansk [536]
3 years ago
14

Write 192.07 in words

Mathematics
2 answers:
Pavel [41]3 years ago
7 0

Answer:

one hundred and ninety two point zero seven

Step-by-step explanation:

idk guess

quester [9]3 years ago
7 0

Answer:

One hundred ninety-two point zero seven

Step-by-step explanation:


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Daily-high temperature measurements for 40 consecutive days are recorded for a particular city. The mean daily-high temperature
Vesnalui [34]

Answer:

t=\frac{21.5-22}{\frac{1.5}{\sqrt{40}}}=-2.108    

p_v =P(t_{39}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean temperature actually its NOT significant less then 22 at 1% of signficance.  

(D) P-val=0.021, fail to reject the null hypothesis

Step-by-step explanation:

1) Data given and notation  

\bar X=21.5 represent the mean for the temperatures

s=1.5 represent the sample standard deviation

n=40 sample size  

\mu_o =22 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is less than 22C, the system of hypothesis would be:  

Null hypothesis:\mu \geq 22  

Alternative hypothesis:\mu < 22  

If we analyze the size for the sample is > 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{21.5-22}{\frac{1.5}{\sqrt{40}}}=-2.108    

P-value

We can calculate the degrees of freedom like this:

df=n-1=40-1=39

Since is a one left tailed test the p value would be:  

p_v =P(t_{39}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean temperature actually its NOT significant less then 22 at 1% of signficance.  

The best option would be:

(D) P-val=0.021, fail to reject the null hypothesis

5 0
3 years ago
Which body parts do birds have? scales, teeth, and beaks feathers, beaks, and hair feathers, beaks, and teeth feathers, beaks, a
Annette [7]

Answer:

head, back, throat, breast, wings, tail, and legs

7 0
3 years ago
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One baseball team won 12 games throughout their entire season. Of all their games this team won 60% of them. Given this how many
Lorico [155]
The basketball team lost 1/2 a game and 1/2 won a game so 1/2

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3 years ago
In triangle ABC, and C is a right angle. Find the value of the trig function find the sec(A) if C=25, B=20, A=15
asambeis [7]

Answer:

sec A = 5/4

Step-by-step explanation:

Sec of an angle is hypotenuse/adjacent side

In your problem, sec A = 25/20 = 5/4

It helps if you can draw a figure of the problem.  Make sure you memorize the definition of each trig function

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A radio commercial for a loan company states: “You only pay $0.29 a day for
yuradex [85]
A loan of $1500 attracts a daily interest of 3(0.29) = $0.87
For 120 days you pay $0.87 x 120 = $104.40 interest.

I = PrT; where P is the principal, r is the annual interest rate and T is the time.
500 x r x 1/365 = 0.29
r = 0.29 x 365 / 500 = 105.85/500 = 0.2117

Therefore,, Annual interest rate = 21.17%
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3 years ago
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