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chubhunter [2.5K]
3 years ago
10

Given the line 2x + 3y = 5, write an equation for a line in slope intercept form that is parallel

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
8 0
Add 2x plus 3y so then you get 5
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What is 86 over 5 as a mixed number in simplest form
inysia [295]
86/5 

= 85/5 + 1/5

= (17x5)/5 + 1/5

= 17 + 1/5
3 0
3 years ago
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the scientists collection that as granite that weighs 74 26/36 lbs, marble that weighs 63 16/34 lbs, and quartz that weighs 81 9
ipn [44]

Answer:

<h2> 6 1/2 lbs</h2>

Step-by-step explanation:

Given the weight of granite to be  74 26/36 lbs,

Weight of quartz is 81 9/40 lbs.

To know how much more quartz weight than the granite, we will take the difference between the weight of quartz and granite as shown.

Weight of quartz  - Weight of granite

= 81 9/40 - 74 26/36

= 3,249/40 - 2690/36

= (29, 241 - 26,900)/360

= 2,341/360

= 6 181/360

≈ 6 1/2 lbs

quartz weighs approximately 6 1/2 lbs much more than granite

7 0
2 years ago
Someone please help !! I don’t know what I’m doing with this !!
dimulka [17.4K]

Answer:

  a) d(sinh(f(x)))/dx = cosh(f(x))·df(x)/dx

  b) d(cosh(f(x))/dx = sinh(f(x))·df(x)/dx

  c) d(tanh(f(x))/dx = sech(f(x))²·df(x)/dx

  d) d(sech(4x+2))/dx = -4sech(4x+2)tanh(4x+2)

Step-by-step explanation:

To do these, you need to be familiar with the derivatives of hyperbolic functions and with the chain rule.

The chain rule tells you that ...

  (f(g(x)))' = f'(g(x))g'(x) . . . . where the prime indicates the derivative

The attached table tells you the derivatives of the hyperbolic trig functions, so you can answer the first three easily.

__

a) sinh(u)' = sinh'(u)·u' = cosh(u)·u'

For u = f(x), this becomes ...

  sinh(f(x))' = cosh(f(x))·f'(x)

__

b) After the same pattern as in (a), ...

  cosh(f(x))' = sinh(f(x))·f'(x)

__

c) Similarly, ...

  tanh(f(x))' = sech(f(x))²·f'(x)

__

d) For this one, we need the derivative of sech(x) = 1/cosh(x). The power rule applies, so we have ...

  sech(x)' = (cosh(x)^-1)' = -1/cosh(x)²·cosh'(x) = -sinh(x)/cosh(x)²

  sech(x)' = -sech(x)·tanh(x) . . . . . basic formula

Now, we will use this as above.

  sech(4x+2)' = -sech(4x+2)·tanh(4x+2)·(4x+2)'

  sech(4x+2)' = -4·sech(4x+2)·tanh(4x+2)

_____

Here we have used the "prime" notation rather than d( )/dx to indicate the derivative with respect to x. You need to use the notation expected by your grader.

__

<em>Additional comment on notation</em>

Some places we have used fun(x)' and others we have used fun'(x). These are essentially interchangeable when the argument is x. When the argument is some function of x, we mean fun(u)' to be the derivative of the function after it has been evaluated with u as an argument. We mean fun'(u) to be the derivative of the function, which is then evaluated with u as an argument. This distinction makes it possible to write the chain rule as ...

  f(u)' = f'(u)u'

without getting involved in infinite recursion.

7 0
2 years ago
What are the coordinates of D' after its preimage, D(4, -8), is reflected over the line y = x?
olya-2409 [2.1K]

Answer: D' is (-8,4)

Step-by-step explanation: The rule for reflection y=x is (x,y)>( y,x) So when  relecting over the axis y=x the x cordinate and the y cordinate switch places.

6 0
2 years ago
Mika read a 405- page book in 6 hours, how many pages per minute did she read?
barxatty [35]
Divide 405 by 6 which is 67.5
So 67.5 per hour but it wants minutes
So divide 67.5 by 60 (minutes in an hour) and you’ll get 1.125 pages per minute
6 0
3 years ago
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